Problem 1
Question
$$\text { In Exercises } 1-14, \text { solve the system of equations using the elimination method.}$$ $$\left\\{\begin{array}{l} x+y=1 \\ x-y=3 \end{array}\right.$$
Step-by-Step Solution
Verified Answer
x = 2, y = -1
1Step 1 - Write the System of Equations
The given system of equations is: \ \( x + y = 1 \) \ \( x - y = 3 \)
2Step 2 - Add the Equations
Add the two equations together to eliminate one variable: \ \( (x + y) + (x - y) = 1 + 3 \) This simplifies to: \ \( 2x = 4 \)
3Step 3 - Solve for x
Divide both sides of the equation by 2 to solve for \( x \): \ \( x = 2 \)
4Step 4 - Substitute x Back into One of the Original Equations
Substitute \( x = 2 \) into the first equation \( x + y = 1 \): \ \( 2 + y = 1 \)
5Step 5 - Solve for y
Subtract 2 from both sides to solve for \( y \): \ \( y = 1 - 2 \) \ \( y = -1 \)
6Step 6 - Check the Solution
Ensure the solution \( x = 2 \) and \( y = -1 \) satisfies both original equations: \ For \( x + y = 1 \): \ \( 2 - 1 = 1 \) (True) \ For \( x - y = 3 \): \ \( 2 - (-1) = 3 \) (True)
Key Concepts
Solving Systems of EquationsSubstitutionLinear Equations
Solving Systems of Equations
A system of equations consists of two or more equations with the same set of variables. Solving these systems means finding the set of values for the variables that satisfy all the equations simultaneously.
There are multiple methods to solve systems of equations:
There are multiple methods to solve systems of equations:
- Graphical Method - Plotting the equations on a graph and finding their intersection points.
- Substitution Method - Solving one equation for one variable and substituting that solution in the other equation.
- Elimination Method - Adding or subtracting equations to eliminate one of the variables, making it easier to solve for the remaining variable.
Substitution
The substitution method involves solving one of the equations for one variable, and then replacing that variable in the other equation with the solved value. This method simplifies solving for the remaining variable by reducing the number of variables in the equation.
In our solved example, after we found that x = 2 using the elimination method, we substituted this value into one of the original equations to find y. Here's how it works:
In our solved example, after we found that x = 2 using the elimination method, we substituted this value into one of the original equations to find y. Here's how it works:
- Step 1: Choose an equation and solve for one variable. (In elimination, this step might come after addition or subtraction.)
- Step 2: Substitute the solved value into the other equation.
- Step 3: Simplify and solve for the remaining variable.
Linear Equations
Linear equations are equations of the first degree, which means they have no exponents higher than one. They graph as straight lines, and a system of linear equations represents multiple straight lines.
The general form of a linear equation is: \[ ax + by = c \], where a, b, and c are constants, and x and y are variables.
To solve systems of linear equations, we can use either the elimination method or substitution method. Each technique leverages the property that linear equations graphically represent straight lines that intersect at points, and those points of intersection represent the solutions to the system.
In our example, the system of equations: \( x + y = 1 \) \( x - y = 3 \), consists of two linear equations representing two straight lines. When solved correctly, as we did, x = 2 and y = -1 is the point of intersection that satisfies both equations.
The general form of a linear equation is: \[ ax + by = c \], where a, b, and c are constants, and x and y are variables.
To solve systems of linear equations, we can use either the elimination method or substitution method. Each technique leverages the property that linear equations graphically represent straight lines that intersect at points, and those points of intersection represent the solutions to the system.
In our example, the system of equations: \( x + y = 1 \) \( x - y = 3 \), consists of two linear equations representing two straight lines. When solved correctly, as we did, x = 2 and y = -1 is the point of intersection that satisfies both equations.
Other exercises in this chapter
Problem 1
A potter has fixed costs of \(\$ 80 .\) It costs her \(\$ 12\) to produce each piece, and she sells each piece for \(\$ 20 .\) Therefore, her total cost \(C\) f
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Solve each of the following verbal problems algebraically. You may use either a oneor a two-variable approach. The sum of two numbers is 130. If their differenc
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A small software firm has a new computer game that it wants to market on a CD- ROM. The fixed costs are \(\$ 2400\), and it costs \(\$ 6\) to produce each CD- R
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$$\text { In Exercises } 1-14, \text { solve the system of equations using the elimination method.}$$ $$\left\\{\begin{array}{l} x-y=4 \\ x+y=6 \end{array}\righ
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