Problem 1
Question
A potter has fixed costs of \(\$ 80 .\) It costs her \(\$ 12\) to produce each piece, and she sells each piece for \(\$ 20 .\) Therefore, her total cost \(C\) for producing \(n\) pieces is given by the equation \(C=80+12 n .\) Her total revenue \(R\) for producing \(n\) pieces is given by the equation \(R=20 n\). (A) Sketch the graph of both equations on the same coordinate system, labeling the horizontal axis \(n\) (B) The potter will break even when her costs and revenue are equal. Use the graph in part (a) to determine the point at which the two lines cross. This is called the break-even point. (C) How many pieces must she sell to break even?
Step-by-Step Solution
Verified Answer
She must sell 10 pieces to break even.
1Step 1: Identify the equations
The total cost equation is given by \[C = 80 + 12n\], and the total revenue equation is given by \[R = 20n\].
2Step 2: Setup the coordinate system
The horizontal axis represents the number of pieces, \(n\), and the vertical axis represents the cost and revenue in dollars.
3Step 3: Plot the Total Cost equation
To plot \[C = 80 + 12n\], choose a few values of \(n\) and calculate \(C\). For example, if \(n = 0\), then \(C = 80\). If \(n = 1\), then \(C = 92\). Plot these points on the graph and draw the line.
4Step 4: Plot the Total Revenue equation
To plot \[R = 20n\], choose a few values of \(n\) and calculate \(R\). For example, if \(n = 0\), then \(R = 0\). If \(n = 1\), then \(R = 20\). Plot these points on the graph and draw the line.
5Step 5: Determine the break-even point
Find the point where the two lines \(C = 80 + 12n\) and \(R = 20n\) intersect. Set the equations equal to each other: \[80 + 12n = 20n\].
6Step 6: Solve for \(n\)
Solve the equation from the previous step: \[80 + 12n = 20n\]. Subtract \(12n\) from both sides: \[80 = 8n\]. Then, divide both sides by 8: \[n = 10\].
7Step 7: Interpret the graph
Verify the intersection by checking the graph. The lines intersect at the point where \(n = 10\).
8Step 8: State the break-even point
The break-even point is where the total cost equals the total revenue, and from our calculation and graph, this occurs at \(n = 10\).
Key Concepts
fixed coststotal cost equationtotal revenue equationgraphing linear equations
fixed costs
Fixed costs are the expenses that do not change regardless of the number of goods produced. In this potter's case, she has fixed costs of \(\text{\textdollar}80\). This amount will stay the same whether she produces zero or a thousand pieces.
Examples of fixed costs include:
Examples of fixed costs include:
- Rent for workshop space
- Insurance
- Salaries of permanent employees
total cost equation
The total cost equation combines fixed and variable costs to show the complete expense of producing goods. For the potter, the equation is given by \(C = 80 + 12n\).
- \(C\) represents the total cost
- \(80\) is the fixed cost
- \(12n\) is the variable cost, where \(12\) is the cost per piece and \(n\) is the number of pieces
- Substitute the number of pieces produced into \(n\)
- Multiply the cost per piece by \(n\)
- Add the fixed cost to get the total cost
total revenue equation
The total revenue equation shows the income generated from selling goods. For the potter, the equation is \(R = 20n\).
- \(R\) represents the total revenue
- \(20n\) shows that each piece is sold for \(\text{\textdollar}20\)
- Multiply the selling price per piece by the number of pieces sold \(n\)
graphing linear equations
Graphing linear equations helps visualize relationships between variables. In this example, we graph the total cost and total revenue equations on the same coordinate system.
Steps to graph both equations:
Steps to graph both equations:
- Set up the coordinate system with the number of pieces \(n\) on the horizontal axis and cost/revenue on the vertical axis.
- Choose values for \(n\) and calculate corresponding \(C\) and \(R\).
- Plot points for each equation and draw the lines.
- Plot the cost line \(C = 80 + 12n\) with points like \((0, 80)\) and \((1, 92)\)
- Plot the revenue line \(R = 20n\) with points like \((0, 0)\) and \((1, 20)\)
Other exercises in this chapter
Problem 1
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