Problem 1
Question
Tell whether each statement is true or false. If a function \(f\) is defined at \(x=a,\) then \(\lim f(x)\) is always equal to \(f(a)\)
Step-by-Step Solution
Verified Answer
False.
1Step 1: Understanding the Limit Concept
The statement talks about the limit of a function \(f(x)\) as \(x\) approaches a certain point \(a\), and whether it is equal to \(f(a)\), the function's value at that point. This involves understanding what a limit and function value mean separately.
2Step 2: Consider the Definition of a Limit
The limit \(\lim_{x \to a} f(x) = L\) means that as \(x\) gets closer and closer to \(a\), \(f(x)\) gets closer to \(L\). However, the limit does not require that \(f(a)\) be equal to \(L\), only that \(f(x)\) is close to \(L\) as \(x\) approaches \(a\).
3Step 3: Analyze Function Continuity
A function \(f\) is continuous at \(x = a\) if \(\lim_{x \to a} f(x) = f(a)\). The statement assumes continuity, but functions can also be discontinuous. For example, in cases like a removable discontinuity, \(\lim_{x \to a} f(x)\) might exist and be different from \(f(a)\).
4Step 4: Determine the Truth of the Statement
Although a function can be defined at \(x = a\), \(\lim_{x \to a} f(x) = f(a)\) is only true if \(f\) is continuous at that point. Hence, the statement is false because it overlooks the possibility of discontinuities where \(\lim_{x \to a} f(x)eq f(a)\).
Key Concepts
Function ContinuityRemovable DiscontinuityLimit Definition
Function Continuity
Continuity is one of the foundational concepts in calculus, and it refers to how a function behaves at certain points or over intervals. For a function to be continuous at a particular point, three main conditions must be met:
- The function must be defined at the point, meaning the output exists and is finite, i.e., \( f(a) \) should be defined.
- The limit of the function as it approaches the point should exist.
- The value of the function at that point must equal the limit, i.e., \( \lim_{x \to a} f(x) = f(a) \).
Removable Discontinuity
A removable discontinuity occurs at a point where a function is not continuous but can be made continuous by redefining the function's value at that point. Typically, this type of discontinuity happens when a function has a "hole" due to an undefined value or a defined value that doesn't match the limit.
Here’s how it typically manifests:
Here’s how it typically manifests:
- The function is not continuous, but the left-hand and right-hand limits are equal.
- The limit exists, i.e., \( \lim_{x \to a} f(x) = L \), but \( f(a) eq L \) or is undefined.
Limit Definition
The limit of a function is a critical concept that deals with the behavior of the function's output as the input approaches a certain value. Specifically, the limit \( \lim_{x \to a} f(x) = L \) means that as \( x \) gets arbitrarily close to \( a \), \( f(x) \) gets arbitrarily close to \( L \).
Understanding limits helps in analyzing how functions behave near points of interest on their domain. It is essential in understanding how to differentiate and integrate functions. Here are key points about limits:
Understanding limits helps in analyzing how functions behave near points of interest on their domain. It is essential in understanding how to differentiate and integrate functions. Here are key points about limits:
- Limits can exist, even if the function is not defined at that point.
- The notion of getting arbitrarily close is separate from actually reaching a value.
- Limits consider the value approached, not necessarily the value achieved by the function at that point.
Other exercises in this chapter
Problem 1
Determine each limit. Refer to the accompanying graph of \(y=f(x)\) when it is given. Do not use a calculator. (a) \(\lim _{x \rightarrow 2^{+}} f(x)\) (b) \(\l
View solution Problem 1
Let \(\lim _{x \rightarrow 4} f(x)=16\) and \(\lim _{x \rightarrow 4} g(x)=8 .\) Use the limit rules to find each limit. Do not use a calculator. $$\lim _{x \ri
View solution Problem 2
Use the midpoint rule with \(n=4\) to approximate the area above the \(x\) -axis bounded by the graph of $$f(x)=\sqrt{16-x^{2}}$$ in the first quadrant.
View solution Problem 2
Let \(\lim _{x \rightarrow 4} f(x)=16\) and \(\lim _{x \rightarrow 4} g(x)=8 .\) Use the limit rules to find each limit. Do not use a calculator. $$\lim _{x \ri
View solution