Problem 1
Question
Determine each limit. Refer to the accompanying graph of \(y=f(x)\) when it is given. Do not use a calculator. (a) \(\lim _{x \rightarrow 2^{+}} f(x)\) (b) \(\lim _{x \rightarrow 2^{-}} f(x)\) where \(f(x)=\left\\{\begin{array}{ll}x & \text { if } x<2 \\ 3 & \text { if } x=2 \\ 4 & \text { if } x>2\end{array}\right.\) (GRAPH CANNOT COPY).
Step-by-Step Solution
Verified Answer
(a) 4; (b) 2.
1Step 1: Understand the Problem
We need to determine two one-sided limits of the function \( f(x) \) as \( x \) approaches 2 from the right and from the left. The function \( f(x) \) is piecewise, meaning it has different expressions based on the values of \( x \).
2Step 1: Determine \( \lim_{x \to 2^+} f(x) \)
To find the limit as \( x \) approaches 2 from the right, consider the expression for \( f(x) \) when \( x > 2 \). Here, \( f(x) = 4 \) for \( x > 2 \), so as \( x \) approaches 2 from the right, \( f(x) \) approaches 4. Thus, \( \lim_{x \to 2^+} f(x) = 4 \).
3Step 2: Determine \( \lim_{x \to 2^-} f(x) \)
For the limit as \( x \) approaches 2 from the left, we use the expression for \( f(x) \) when \( x < 2 \). Here, \( f(x) = x \), so as \( x \to 2 \) from the left, \( f(x) \) approaches 2. Therefore, \( \lim_{x \to 2^-} f(x) = 2 \).
4Step 4: Summarize Findings
We found that \( \lim_{x \to 2^+} f(x) = 4 \) and \( \lim_{x \to 2^-} f(x) = 2 \). These one-sided limits indicate that \( \lim_{x \to 2} f(x) \) does not exist because the one-sided limits are not equal.
Key Concepts
Piecewise FunctionsOne-Sided LimitsApproaching from the Right and Left
Piecewise Functions
Piecewise functions are functions defined by different expressions depending on the value of the input variable. They allow us to model a variety of real-world situations where a single expression isn't sufficient. For the function in the exercise, you can see that:
- If \(x < 2\), then \(f(x) = x\). This means that for any value of \(x\) less than 2, the output of the function is simply \(x\) itself.
- If \(x = 2\), the function jumps to \(f(x) = 3\). Here, the value is explicitly stated.
- For \(x > 2\), the function gives \(f(x) = 4\).
One-Sided Limits
One-sided limits are a fundamental concept when working with piecewise functions. Instead of looking at the behavior as \(x\) approaches a point from both sides, we isolate each side:
- A limit from the right, denoted \(\lim_{x \to 2^+} f(x)\), means we only consider the values of \(x\) that are greater than 2, approaching 2.
- A limit from the left, denoted \(\lim_{x \to 2^-} f(x)\), involves values of \(x\) that are less than 2, getting closer to 2.
Approaching from the Right and Left
When a function behaves differently as you approach a particular point from the right and from the left, it's important to take note of this difference.
Understanding Right-Sided Limits
When \(x\) approaches 2 from the right (i.e., \(x > 2\)), the function in our example gives \(f(x) = 4\). As \(x\) closes in on 2 from this side, you consistently get closer to the value 4.Understanding Left-Sided Limits
By contrast, when \(x\) approaches 2 from the left (\(x < 2\)), the function follows \(f(x) = x\), meaning that as \(x\) nears 2, \(f(x)\) tends towards 2.Because the value approaching from the right, \(4\), differs from the value from the left, \(2\), the two sides do not meet at the same point. Hence, the overall limit \(\lim_{x \to 2} f(x)\) cannot exist, illustrating the importance of considering each side separately to determine the behavior at discontinuities.Other exercises in this chapter
Problem 1
Let \(f(x)=2 x+1, x_{1}=0, x_{2}=2, x_{3}=4, x_{4}=6,\) and \(\Delta x=2\) (a) Find \(\sum_{i=1}^{4} f\left(x_{i}\right) \Delta x\) (b) The sum in part (a) appr
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Let \(\lim _{x \rightarrow 4} f(x)=16\) and \(\lim _{x \rightarrow 4} g(x)=8 .\) Use the limit rules to find each limit. Do not use a calculator. $$\lim _{x \ri
View solution Problem 1
Tell whether each statement is true or false. If a function \(f\) is defined at \(x=a,\) then \(\lim f(x)\) is always equal to \(f(a)\)
View solution Problem 2
Use the midpoint rule with \(n=4\) to approximate the area above the \(x\) -axis bounded by the graph of $$f(x)=\sqrt{16-x^{2}}$$ in the first quadrant.
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