Problem 1
Question
Specify the domain of the function $$ f(x)=\frac{2 x-1}{\sqrt{4-x^{2}}} $$
Step-by-Step Solution
Verified Answer
The domain of the function is (-2, 2).
1Step 1: Identify conditions for the denominator
The function has a fraction with a denominator containing a square root. For the square root to be a real number, the expression inside it must be non-negative (since the square root of a negative number is undefined in the set of real numbers). So, we need to solve the inequality: The square root function is defined when the expression under the radical is positive: 4 - x^2 > 0
2Step 2: Solve the inequality
Solve the inequality found in Step 1. First, rewrite the inequality: 4 - x^2 > 02. Isolate the term involving x: -x^2 > -4.2. Then, divide both sides by -1 (remember to reverse the inequality sign when dividing by a negative number): x^2 < 4.Taking the square root of both sides results in: -2 < x < 2.
3Step 3: Exclude points where the denominator becomes zero
The function is undefined where the denominator is zero. Thus, for The function changes its slope when the denominator is zero: sqrt (4 - x^2) = 0,4 - x^2 = 0,x^2 = 4,Solving this gives the points x = -2 and x =2.Therefore, these points must be excluded from the domain.
4Step 4: Combine the results
Taking all conditions into account, the domain of f(x) excludes the points x = -2 and x =2 but includes all values between them. Thus, the domain of f(x) is: xi n( -2, 2).
Key Concepts
Inequalities in CalculusFractional FunctionsDomain Restrictions
Inequalities in Calculus
When working with calculus and functions, inequalities help us determine the range of valid input values (domain) for which a function is defined. In the provided exercise, we encounter the inequality involving the term under the square root: 4 - x^2 > 0This inequality is critical because the square root function is only defined for non-negative numbers. Here are the steps to solve this inequality:
- Rearrange the inequality: -x² > -4
- Divide by -1 (remember to flip the inequality sign): x² < 4
- Take the square root of both sides: -2 < x < 2
Fractional Functions
Fractional functions are functions that contain fractions where the numerator and/or the denominator involve variables. In our example, the function is: \[ f(x) = \frac{2x - 1}{\text{sqrt}(4 - x^2)} \] For fractional functions, it is essential that the denominator does not become zero, because division by zero is undefined. In this case, the denominator is \( \text{sqrt}(4 - x^2) \). From earlier, we know that the denominator is defined if 4 - x^2 > 0. However, we also need to ensure 4 - x^2 ≠ 0 because that would make the denominator zero. Solving 4 - x^2 = 0 gives us x = ±2, which we must exclude from our domain, narrowing it down further.
Domain Restrictions
Domain restrictions are constraints on the input values of a function to ensure it is well-defined (non-zero denominators and real numbers under square roots, etc.). For the function \( f(x) = \frac{2x - 1}{\text{sqrt}(4 - x^2)} \), we face multiple restrictions:
- The inequality we solved previously: -2 < x < 2
- Excluding points where the denominator zeroes out: x ≠ -2 and x ≠ 2
Other exercises in this chapter
Problem 2
Find the composite function \(g(h(x))\), where \(g(u)=\frac{1}{2 u+1}\) and \(h(x)=\frac{x+2}{2 x+1}\)
View solution Problem 3
Find an equation for each of these lines: a. Through the point \((-1,2)\) with slope \(-\frac{1}{2}\) b. With slope 2 and \(y\) intercept \(-3\)
View solution Problem 4
Sketch the graph of each of these functions. Be sure to show all intercepts and any high or low points. a. \(f(x)=3 x-5\) b. \(f(x)=-x^{2}+3 x+4\)
View solution