Problem 1
Question
In Exercises 1 through 4 , find the slope of the line through the given points. $$ (2,-3),(-4,3) $$
Step-by-Step Solution
Verified Answer
The slope is -1.
1Step 1: Understand the Slope Formula
The formula to find the slope (m) between two points \(x_1, y_1\) and \(x_2, y_2\) is: \[ m = \frac{y_2 - y_1}{x_2 - x_1} \] where \(x_1, y_1\) and \(x_2, y_2\) are the coordinates of the two points.
2Step 2: Identify the Coordinates
Identify the coordinates of the given points: \(x_1 = 2, y_1 = -3\) and \(x_2 = -4, y_2 = 3\).
3Step 3: Substitute the Coordinates into the Formula
Substitute the values into the slope formula: \[ m = \frac{3 - (-3)}{-4 - 2} \]
4Step 4: Simplify the Expression
Simplify the numerator and the denominator: \[ m = \frac{3 + 3}{-4 - 2} = \frac{6}{-6} = -1 \]
5Step 5: Interpret the Result
The slope \(m\) of the line passing through the points (2, -3) and (-4, 3) is -1.
Key Concepts
Slope FormulaCoordinate GeometryLinear EquationsPoint-Slope Form
Slope Formula
The slope of a line measures its steepness and direction. It's an important concept in algebra and coordinate geometry, often referred to as the 'rise over run.' To find the slope, we often use the slope formula:
- The slope formula is given by \[ m = \frac{y_2 - y_1}{x_2 - x_1} \]
- Here, \(x_1, y_1\) and \(x_2, y_2\) are the coordinates of two distinct points on the line.
Coordinate Geometry
Coordinate geometry, also known as analytic geometry, is the study of geometry using a coordinate system.
Imagine the x-axis and y-axis on a plane, which help in locating points called coordinates. The basics involve understanding how points, lines, and shapes are positioned and how they relate to each other. Here are some key points:
Imagine the x-axis and y-axis on a plane, which help in locating points called coordinates. The basics involve understanding how points, lines, and shapes are positioned and how they relate to each other. Here are some key points:
- The coordinates (or ordered pairs) are written as \(x, y\).
- The x-coordinate is the location of the point along the horizontal axis.
- The y-coordinate is the position along the vertical axis.
For example,
The point (2, -3) lies 2 units to the right and 3 units downward from the origin (0,0). Similarly, the point (-4, 3) is 4 units left and 3 units up from the origin. Understanding coordinate geometry is fundamental to solving problems like finding the slope of a line. It helps you visualize and interpret the spatial relationships between different elements on the plane.
Linear Equations
Linear equations describe straight lines in coordinate geometry. These are algebraic equations that have a constant rate of change and can be written in several forms:
- Standard Form: \[ Ax + By = C \]
- Slope-Intercept Form: \[ y = mx + b \]
Point-Slope Form
The point-slope form of a linear equation is particularly useful when you know the slope and one point on the line. It is written as: \[ y - y_1 = m(x - x_1) \]
Here:
Starting with the slope -1 and a point, for instance, (2,-3), you can use the point-slope formula to find the linear equation.Substituting \(m = -1\) and \(x_1 = 2, y_1 = -3\):\[ y - (-3) = -1(x - 2) \]
By simplifying, you get
\[ y + 3 = -1(x - 2)\]Then, distribute and rearrange to standard or slope-intercept form, depending on what you need. Point-slope form makes it easier to write equations when data is limited and clear understanding of these equations will ease up tasks of finding lines equations straightforwardly.
Here:
- \(m\) is the slope
- \(x_1, y_1\) is a point on the line
Starting with the slope -1 and a point, for instance, (2,-3), you can use the point-slope formula to find the linear equation.Substituting \(m = -1\) and \(x_1 = 2, y_1 = -3\):\[ y - (-3) = -1(x - 2) \]
By simplifying, you get
\[ y + 3 = -1(x - 2)\]Then, distribute and rearrange to standard or slope-intercept form, depending on what you need. Point-slope form makes it easier to write equations when data is limited and clear understanding of these equations will ease up tasks of finding lines equations straightforwardly.
Other exercises in this chapter
Problem 1
In Exercises 1 through 10, solve for \(x\). $$ |4 x+3|=7 $$
View solution Problem 1
In Exercises 1 through 6, plot the given point \(P\) and such of the following points as may apply: (a) The point \(Q\) such that the line through \(Q\) and \(P
View solution Problem 2
Given \(g(x)=3 x^{2}-4\), find: (a) \(g(-4)\) (b) \(g\left(\frac{1}{2}\right)\) (c) \(g\left(x^{2}\right)\) (d) \(g\left(3 x^{2}-4\right)\) (e) \(g(x-h)\) (f) \
View solution Problem 2
In Exercises 1 through 10 , find the domain and range of the given function, and draw a sketch of the graph of the function. $$ g=\left\\{(x, y) \mid y=x^{2}+2\
View solution