Problem 1
Question
Find the coordinates of the focus and the equation of the directrix for each parabola. Make a sketch showing the parabola, its focus, and its directrix. $$ y^{2}=4 x $$
Step-by-Step Solution
Verified Answer
Focus: (1,0). Directrix: x = -1.
1Step 1: Identify the form of the equation
The given equation is \( y^2 = 4x \), which is a parabola that opens horizontally. This matches the standard form \( y^2 = 4px \), where \( p \) determines the distance from the vertex to the focus and the directrix.
2Step 2: Determine the value of p
By comparing \( y^2 = 4x \) to the standard form \( y^2 = 4px \), we see that \( 4p = 4 \). Solving for \( p \), we get \( p = 1 \).
3Step 3: Find the vertex of the parabola
For \( y^2 = 4px \), the vertex is at the origin \((0,0)\).
4Step 4: Locate the focus
Since the parabola opens to the right and \( p = 1 \), the focus is located \( p \) units to the right of the vertex. Thus, the focus is at \( (1,0) \).
5Step 5: Write the equation of the directrix
The directrix is a vertical line \( p \) units to the left of the vertex. Given \( p = 1 \), the equation of the directrix is \( x = -1 \).
6Step 6: Make a sketch
Draw a horizontal parabola opening to the right with the vertex at \((0,0)\). Plot the focus at \((1,0)\) and the directrix line at \( x = -1 \).
Key Concepts
Focus of a ParabolaDirectrix of a ParabolaVertex of a ParabolaEquation of a Parabola
Focus of a Parabola
The focus of a parabola is a specific point located in relation to the vertex. It plays an integral role in defining the shape and direction of the parabola. In the equation of a parabola that opens horizontally, like in the form \( y^2 = 4px \), the focus is found \( p \) distance from the vertex. Here, \( p \) represents the distance from the vertex to the focus along the axis of symmetry of the parabola.
For example, in the parabola described by the equation \( y^2 = 4x \):
For example, in the parabola described by the equation \( y^2 = 4x \):
- We find \( p = 1 \) by comparing it to the standard form \( y^2 = 4px \).
- The focus is then located at \((p, 0) = (1, 0)\) because the parabola opens to the right.
Directrix of a Parabola
The directrix of a parabola is a crucial component that, together with the focus, defines the parabola's properties. It is a straight line that is perpendicular to the axis of symmetry of the parabola.
For parabolas in the form \( y^2 = 4px \), like our example \( y^2 = 4x \), the directrix is located at a distance \( p \) units away from the vertex, opposite the focus. This means:
For parabolas in the form \( y^2 = 4px \), like our example \( y^2 = 4x \), the directrix is located at a distance \( p \) units away from the vertex, opposite the focus. This means:
- If the parabola opens to the right, as in \( y^2 = 4x \), the directrix will be a vertical line to the left of the vertex.
- So, for \( p = 1 \), the directrix is at \( x = -1 \) since it is \( p \) units left of the vertex \((0, 0)\).
Vertex of a Parabola
The vertex of a parabola is the point where the parabola changes direction and is either the highest or lowest point, depending on its orientation. In equations like \( y^2 = 4px \), the vertex often serves as the reference point for locating both the focus and the directrix. For the equation \( y^2 = 4x \), the vertex is straightforward to determine:
- The vertex is at the origin, \((0,0)\), because there is no constant term shifting the parabola from this position.
- This vertex is the midpoint between the focus \((1,0)\) and the directrix \( x=-1 \), serving as the base from which the parabola expands.
Equation of a Parabola
The equation of a parabola gives us critical information about its shape and direction. Parabolas that open sideways, like in the form \( y^2 = 4px \), have an axis of symmetry that is horizontal. The distance \( p \) determines how wide or narrow the parabola is and its direction from the vertex.
In our example, the equation:
In our example, the equation:
- \( y^2 = 4x \) indicates a horizontal parabola opening to the right.
- The coefficient 4 represents \( 4p \) where \( p \) is the distance from the vertex to the focus and directrix, calculated as \( p = 1 \).
Other exercises in this chapter
Problem 1
a parametric representation of a curve is given. $$ x=3 t, y=2 t ;-\infty
View solution Problem 1
Name the conic (horizontal ellipse, vertical hyperbola, and so on) corresponding to the given equation. $$ \frac{x^{2}}{9}+\frac{y^{2}}{4}=1 $$
View solution Problem 2
Name the conic or limiting form represented by the given equation. Usually you will need to use the process of completing the square (see Examples \(3-5) .\) x^
View solution Problem 2
Sketch the graph of the given equation and find the area of the region bounded by it. $$ r=2 a \cos \theta, a>0 $$
View solution