Problem 1
Question
a parametric representation of a curve is given.
$$
x=3 t, y=2 t ;-\infty
Step-by-Step Solution
Verified Answer
The Cartesian equation of the curve is \(y = \frac{2}{3}x\).
1Step 1: Understanding Parametric Equations
The given parametric equations are \(x = 3t\) and \(y = 2t\). These equations express \(x\) and \(y\) as functions of the parameter \(t\). Our job is to eliminate \(t\) to find a relationship between \(x\) and \(y\).
2Step 2: Solving for t in one of the equations
Choose one of the equations to solve for \(t\). Let’s use \(x = 3t\). To isolate \(t\), divide both sides by 3 to get \(t = \frac{x}{3}\).
3Step 3: Substitute t into the other equation
Now, substitute the expression we found for \(t\) in terms of \(x\) into the other equation. So, substitute \(t = \frac{x}{3}\) into \(y = 2t\):\[ y = 2 \left(\frac{x}{3}\right) = \frac{2x}{3}.\]
4Step 4: Presenting the Cartesian Equation
We now have \(y\) in terms of \(x\): \(y = \frac{2}{3}x\). This equation represents the curve in the Cartesian (\(x, y\)) coordinate system, showing the relationship without the parameter \(t\).
Key Concepts
Parametric RepresentationCartesian EquationEliminating Parameter
Parametric Representation
In mathematics, parametric representation is a powerful method to define curves using a set of equations. Instead of describing curves in the traditional X-Y coordinate system, parametric equations use one or more independent variables, known as parameters, to express the coordinates. For example, in the given problem, we have parametric equations:
- \( x = 3t \)
- \( y = 2t \)
Cartesian Equation
A Cartesian equation is what most of us are familiar with when describing curves. It is a direct relationship between \( x \) and \( y \) that does not depend on any other parameter. For the exercise, after finding the parametric equations, next was to derive the Cartesian equation. Using the steps provided, the process started by expressing one of the variables in terms of \( t \), choosing \( x = 3t \). From this, \( t \) was isolated, giving \( t = \frac{x}{3} \).Substituting this into the equation for \( y \), we have:\[y = 2 \left(\frac{x}{3}\right) = \frac{2x}{3}\]This cross-elimination of \( t \) provides a clear functional relationship \( y = \frac{2}{3}x \) , representing the curve directly on the Cartesian plane. The Cartesian form is favored when you want to depict a curve without involving additional parameters.
Eliminating Parameter
One of the main goals in working with parametric equations is often to eliminate the parameter, yielding a Cartesian equation. This process transforms parametric forms into more widely recognized Cartesian forms. To eliminate the parameter \( t \), we start by solving one of the parametric equations for \( t \). In this exercise, \( x = 3t \) is chosen, leading to:\[t = \frac{x}{3}\]Next, substituting this expression into the second equation, \( y = 2t \), provides:\[y = 2\left(\frac{x}{3}\right) = \frac{2x}{3}\] This results in \( y = \frac{2}{3}x \), eliminating \( t \) completely. Such a method is essential for simplifying expressions. It turns complex parametric curves into manageable mathematical expressions that can be easily graphed or further analyzed. Eliminating parameters can also reveal hidden characteristics of the curve, such as slopes or intercepts, assisting in better understanding and interpretation of the mathematical function.
Other exercises in this chapter
Problem 1
Sketch the graph of the given equation and find the area of the region bounded by it. $$ r=a, a>0 $$
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Plot the points whose polar coordinates are \(\left(3, \frac{1}{3} \pi\right)\), \(\left(1, \frac{1}{2} \pi\right),\left(4, \frac{1}{3} \pi\right),(0, \pi),(1,4
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Name the conic (horizontal ellipse, vertical hyperbola, and so on) corresponding to the given equation. $$ \frac{x^{2}}{9}+\frac{y^{2}}{4}=1 $$
View solution Problem 1
Find the coordinates of the focus and the equation of the directrix for each parabola. Make a sketch showing the parabola, its focus, and its directrix. $$ y^{2
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