Problem 1
Question
Find a parametrization of the line that (a) joins the origin to the point \(1+i\). (b) joins the point. 1 to the point \(1+i\). (c) joins the point \(i\) to the point \(1+i\). (d) joins the point 2 to the point \(1+i\).
Step-by-Step Solution
Verified Answer
(a) \( z(t) = t(1+i) \); (b) \( z(t) = 1 + ti \); (c) \( z(t) = i + t(1-t) \); (d) \( z(t) = 2 - t + ti \).
1Step 1: Understanding Parametrization of a Line
To parametrize a line joining two points in the complex plane, we can express it in the form \( z(t) = (1-t)z_0 + tz_1 \), where \( z_0 \) is the starting point, \( z_1 \) is the ending point, and \( t \) is a parameter ranging from 0 to 1.
2Step 2: Parametrization for the Line Joining the Origin to Point 1+i
The line joins the origin (0) to the point \(1+i\). Using \( z_0 = 0 \) and \( z_1 = 1+i \), the parametrization is: \[ z(t) = (1-t) imes 0 + t(1+i) = t(1+i) \].
3Step 3: Parametrization for the Line Joining Point 1 to Point 1+i
The line joins point 1 to \(1+i\). Using \( z_0 = 1 \) and \( z_1 = 1+i \), the parametrization is: \[ z(t) = (1-t) imes 1 + t(1+i) = 1 + ti \].
4Step 4: Parametrization for the Line Joining Point i to Point 1+i
The line joins point \(i\) to \(1+i\). Using \( z_0 = i \) and \( z_1 = 1+i \), the parametrization is: \[ z(t) = (1-t) imes i + t(1+i) = i + t - ti \].
5Step 5: Parametrization for the Line Joining Point 2 to Point 1+i
The line joins point 2 to \(1+i\). Using \( z_0 = 2 \) and \( z_1 = 1+i \), the parametrization is: \[ z(t) = (1-t) imes 2 + t(1+i) = 2 - 2t + t + ti = 2 - t + ti \].
Key Concepts
ParametrizationComplex PlaneLines in Complex Numbers
Parametrization
Parametrization is a powerful concept that allows us to express a geometric object, like a line, using a parameter. Often, the parameter is denoted by a variable such as \( t \). This makes it easier to handle in problems involving motion and time, as well as providing a smooth transition from one point to another. In complex analysis, parametrize means to express points along a line in the complex plane with an equation. Here, the parametric equation of a line joining two points \( z_0 \) and \( z_1 \) in the complex plane is given by:\[z(t) = (1-t)z_0 + tz_1\]
- \( z_0 \) is the starting point.
- \( z_1 \) is the end point.
- \( t \) is a parameter ranging from 0 to 1.
Complex Plane
The complex plane, sometimes referred to as the Argand plane, is a fundamental idea in complex analysis. It provides an intuitive way to visualize complex numbers. Imagine it as a two-dimensional plane similar to the Cartesian coordinate system. In this setup, each complex number \( z = x + yi \) is represented by a point on the plane:
- The horizontal axis (real axis) represents the real part \( x \) of the complex number.
- The vertical axis (imaginary axis) represents the imaginary part \( y \).
Lines in Complex Numbers
Lines in the complex plane are similar to lines in geometry, but with complex numbers as coordinates. When defining a line between two points, say \( z_0 \) and \( z_1 \), it can be visualized as a straight path on the plane. The equation for this would be:\[z(t) = (1-t)z_0 + tz_1\]Here, \( t \) acts as an interpolating factor running from 0 to 1, smoothly transitioning the point along the line.
- When \( t = 0 \), the point is at \( z_0 \).
- When \( t = 1 \), the point reaches \( z_1 \).
- For \( 0 < t < 1 \), the point \( z(t) \) lies somewhere between \( z_0 \) and \( z_1 \).
Other exercises in this chapter
Problem 1
Find \(\mathrm{Arg} z\) for the following values of \(z\). (a) \(1-i\). (b) \(-\sqrt{3}+i\). (c) \((-1-i \sqrt{3})^{2}\) (d) \((1-i)^{3}\). (e) \(\frac{2}{1+i \
View solution Problem 1
Calculate the following. (a) \((1-i \sqrt{3})^{3}(\sqrt{3}+i)^{2}\) (b) \(\frac{(1+6)^{3}}{(1-i)^{3}}\). (c) \((\sqrt{3}+i)^{6}\).
View solution Problem 2
Explain why cubic equations, rather than quadratic equations, played a pivotal role in helping to obtain the acceptance of complex numbers.
View solution Problem 2
Locate \(z_{1}\) and \(z_{2}\) vectorially and use vectors to find \(z_{1}+z_{2}\) and \(z_{1}-z_{2}\) when (a) \(z_{1}=2+3 i\) and \(z_{2}=4+i\) (b) \(z_{1}=-1
View solution