Q. 248 - Intermediate Algebra

Question

In the following exercises, find product of ${\left(a^5\hspace{0.17em}-\hspace{0.17em}7b\right)}^2$.

Step-by-Step Solution

Answer

The product of ${(a^5-7b)}^2$ is $a^{10}-14a^{5}b+49b^2$

Step 1. Given Information

Considering the given expression is ${(a^5-7b)}^2$

Step 2. Solve for the multiplication of given expression.

Multiply the expression ${(a^5-7b)}^2$

$$\begin{gathered} {(a^5-7b)}^2=(a^5-7b)(a^5-7b) \\ (a^5-7b)(a^5-7b)=a^{10}-7a^{5}b-7a^{5}b+49b^2 \\ {a}^{10}-7a^{5}b-7a^{5}b+49b^2=a^{10}-14a^{5}b+49b^2 \end{gathered}$$