Q. 247 - Intermediate Algebra

Question

In the following exercises, find the product of ${\left(k\hspace{0.17em}-\hspace{0.17em}6\right)}^2$ .

Step-by-Step Solution

Answer

The product of ${(k-6)}^2$ is $k^2-12k+36$

Step 1. Given Information

Considering the given expression ${(k-6)}^2$ .

Step 2. Solve for the multiplication of given expression.

Multiply the expression ${(k-6)}^2$ .

$$\begin{gathered} {(k-6)}^2=(k-6)(k-6) \\ (k-6)(k-6)=k^2-6k-6k+36 \\ {k}^2-6k-6k+36=k^2-12k+36 \end{gathered}$$