In the given figure AB || CD, ∠A = 128°, ∠E = 144°. Then, ∠FCD is equal to :
In the given figure AB || CD, ∠A = 128°, ∠E = 144°. Then, ∠FCD is equal to :
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3,094 questions
In the given figure AB || CD, ∠A = 128°, ∠E = 144°. Then, ∠FCD is equal to :
In the trapezium PQRS, QR || PS, ∠Q = 90°, PQ = QR and ∠PRS = 20°. If ∠TSR = θ, then the value of θ is:
In the adjoining figure, ∠ABC = 100°, ∠EDC = 120° and AB || DE. Then, ∠BCD is equal to:
In the given figure, AB || CD, ∠ABO = 40° and ∠CDO = 30°. If ∠DOB = x°, then the value of x is:
In the given figure, AB || CD, m∠ABF = 45° and m∠CFC = 110°. Then, m∠FDC is:
In the given figure, line CE is drawn parallel to DB. If ∠BAD = 110°, ∠ABD = 30°, ∠ADC = 75° and ∠BCD = 60°, then the value of x° is:
In the figure given above, EC is parallel to AB, ∠ECD = 70° and ∠BDO = 20°. What is the value of ∠OBD?
Consider the following statements If two straight lines intersect, then I. vertically opposite angles are equal. II. vertically opposite angles are supplementary. III. adjacent angles are...
In the figure given above LOM is a straight line. What is the value of x°?
Two straight lines AB and CD cut each other at O. If ∠BOD = 63°, then ∠BOC is: