Chapter 2

Applied Mathematics · 19 exercises

Problem 1

A force of \(30 \mathrm{~N}\) is inclined at an angle \(\theta\) to the horizontal. If its vertical component is \(18 \mathrm{~N}\), find the horizontal component and the value of \(\theta\).

4 step solution

Problem 1

The resultant of displacements \(2 \mathrm{~m}\) South, \(4 \mathrm{~m}\) West, \(5 \mathrm{~m}\) North is of magnitude: (a) \(3 \mathrm{~m}\) (b) \(7 \mathrm{~m}\) (c) \(5 \mathrm{~m}\) (d) \(\sqrt{65} \mathrm{~m}\) (e) \(11 \mathrm{~m}\).

4 step solution

Problem 3

The horizontal component of a force of \(10 \mathrm{~N}\) inclined at \(30^{\circ}\) to the vertical is: (a) \(5 \mathrm{~N}\) (b) \(5 \sqrt{3} \mathrm{~N}\) (c) \(3 \mathrm{~N}\) (d) \(\frac{10}{3} \mathrm{~N}\) (e) \(\frac{10}{\sqrt{3}} \mathrm{~N}\)

5 step solution

Problem 4

Forces represented by \(3 \mathbf{i}+5 \mathbf{j}, \mathbf{i}-2 \mathbf{j}\) and \(-3 \mathbf{i}+\mathbf{j}\) together with a fourth force F act on a particle. If the resultant force is represented by \(4 \mathrm{i}+\mathrm{j}\), find \(\mathbf{F}\).

5 step solution

Problem 4

Two vectors inclined at an angle \(\theta\) have magnitudes \(3 \mathrm{~N}\) and \(5 \mathrm{~N}\) and their resultant is of magnitude \(4 \mathrm{~N}\). The angle \(\theta\) is: (a) \(90^{\circ}\) (b) \(\arccos \frac{4}{5}\) (c) \(\arccos \frac{3}{5}\) (d) \(\arccos \frac{-3}{5}\) (e) \(60^{\circ}\)

5 step solution

Problem 5

\(\mathrm{ABCDEF}\) is a regular hexagon. Forces acting along \(\overrightarrow{\mathrm{CB}}, \overrightarrow{\mathrm{CA}}, \overrightarrow{\mathrm{CF}}\) and \(\overrightarrow{\mathrm{CD}}\) are of magnitudes \(2,4,5\) and 6 newton respectively. What is the inclination of their resultant to \(\mathrm{CF}\) ?

7 step solution

Problem 5

Two forces \(F_{1}\) and \(\mathbf{F}_{2}\) have a resultant \(\mathbf{F}_{3}\). If \(\mathrm{F}_{1}=2 \mathbf{i}-3 \mathrm{j}\) and \(\mathbf{F}_{3}=5 \mathbf{i}+4 \mathrm{j}\) then \(\mathbf{F}_{2}\) is: (a) \(7 \mathbf{i}+\mathbf{j}\) (b) \(-3 \mathrm{i}-7 \mathrm{j}\) (c) \(3 \mathrm{i}+7 \mathrm{j}\) (d) \(7 \mathrm{i}+7 \mathbf{j}\)

6 step solution

Problem 6

If a represents a velocity of \(4 \mathrm{~ms}^{-1}\) North East and \(b\) represents a velocity of \(6 \mathrm{~ms}^{-1}\) West, what velocities are represented by: (i) \(-2 \mathrm{a}\) (ii) \(\mathbf{a}+\mathbf{b}\) (iii) \(3 \mathrm{~b}-\mathrm{a}\) ?

4 step solution

Problem 9

\(\mathrm{ABC}\) is an equilateral triangle and \(\mathrm{D}\) is the mid-point of \(\mathrm{BC}\). Forces of 1,2, 4 and \(3 \sqrt{3}\) newton act along \(\overrightarrow{B C}, \overrightarrow{B A}, \overrightarrow{C A}\) and \(\overrightarrow{A D}\) respectively. Resolve each of the forces in the directions \(\mathrm{BC}\) and \(\mathrm{DA}\) and verify that the sum of the components in each direction is zero.

7 step solution

Problem 9

A force \(\mathrm{F}=3 \mathrm{i}+4 \mathrm{j}\). (a) The magnitude of the force is 5 units. (a) The magnitude of the force is 5 units. (b) The component of magnitude 3 units must be horizontal.

4 step solution

Problem 10

A force of \(2 \sqrt{2} \mathrm{~N}\) acts along the diagonal \(\mathrm{AC}\) of a square \(\mathrm{ABCD}\) and another force \(P\) acts along AD. If the resultant force is inclined at \(60^{\circ}\) to \(\mathrm{AB}\) find the value of \(P\).

5 step solution

Problem 13

A quad rilateral \(A B C D\) has opposite sides \(A B\) and DC parallel. Angle \(\mathrm{ABC}=150^{\circ}\) and angle \(\mathrm{BAD}=60^{\circ}\). Forces \(2 P, P, P, 2 P\) act along \(\overrightarrow{\mathrm{AB}}, \overrightarrow{\mathrm{BC}}, \overrightarrow{\mathrm{CD}}\), \(\overrightarrow{A D}\) respectively. Prove that the resultant has magnitude \(P(8+3 \sqrt{3})^{\frac{1}{2}}\) and find the tangent of the angle it makes with \(\mathrm{AB}\).

5 step solution

Problem 13

Calculate the magnitude of the resultant of two forces \(F_{1}\) and \(\mathbf{F}_{2}\). (a) \(\mathrm{F}_{1}=3 \mathrm{i}+7 \mathrm{j}\). b) \(F_{2}=\mathbf{i}-4 \mathbf{j}\) c) Both forces act at a point \(2 \mathrm{i}+\mathrm{j}\).

4 step solution

Problem 15

A plane lamina has perpendicular axes \(O x\) and \(O y\) marked on it, and is acted upon by the following forces: \(5 P\) in the direction \(O y\), \(4 P\) in the direction \(O x\), \(6 P\) in the direction OA where \(A\) is the point \((3 a, 4 a\) ), \(8 P\) in the direction \(\mathrm{AB}\) where \(\mathrm{B}\) is the point \((-a, a)\). Express each force in the form \(p \mathbf{i}+q \mathbf{j}\) and hence calculate the magnitude and direction of the resultant of these forces.

6 step solution

Problem 15

Six forces acting on a particle have directions parallel to the sides \(\mathrm{AB}, \mathrm{BC}\), \(C D\), DE, EF, FA of a hexagon. Find the magnitude and direction of their esultant if: a) the forces have magnitudes \(F, 2 F, 3 F, 2 F, 2 F, F\) respectively, b) the sense of each force is indicated by the order of the letters, (c) the hexagon is regular.

7 step solution

Problem 16

A speedboat which can travel at 20 knots in still water starts from the corner \(X\) of an equilateral triangle \(X Y Z\) of side 10 nautical miles and describes the complete course XYZX in the least possible time. A tide of 5 knots is running in the direction \(\overrightarrow{Z X}\). Find: (a) the speed of the boat along XY, (b) to the nearest minute the time taken by the speedboat to traverse the complete course XYZX. (1 knot is one nautical mile per hour).

8 step solution

Problem 16

Express a force \(\mathbf{F}\) in the form \(a \mathbf{i}+b \mathbf{j}\). (a) The magnitude of the force is \(5 \mathrm{~N}\). (b) The force is inclined at \(60^{\circ}\) to the horizontal. (c) \(\mathrm{j}\) is in the direction of the upward vertical.

5 step solution

Problem 18

Two vectors of equal magnitude and which are in the same direction are. equal vectors.

4 step solution

Problem 21

If \(\mathrm{F}_{1}=2 \mathrm{i}+3 \mathrm{j}\) and \(\mathrm{F}_{2}=2 \mathrm{i}-3 \mathrm{j}\) then \(\mathrm{F}_{1}\) and \(\mathbf{F}_{2}\) are equal and opposite.

5 step solution

Show/ page