Chapter 17
Algebra · 14 exercises
Problem 2
A ring is said to be Artinian if every descending sequence of left ideals \(J_{1} \supset J_{2} \supset \cdots\) with \(J_{i} \neq J_{i+1}\) is finite. (a) Show that a finite dimensional algebra over a field is Artinian. (b) If \(R\) is Artinian, show that every non-zero left ideal contains a simple left ideal. (c) If \(R\) is Artinian, show that every non-empty set of ideals contains a minimal ideal.
3 step solution
Problem 3
Let \(R\) be Artinian. Show that its radical is 0 if and only if \(R\) is semisimple. [Hint: Get an injection of \(R\) into a direct sum \(\oplus R / M_{i}\) where \(\left\\{M_{i}\right\\}\) is a finite set of maximal left ideals.]
3 step solution
Problem 4
Nakayama's lemma. Let \(R\) be any ring and \(M\) a finitely generated module. Let \(N\) be the radical of \(R .\) If \(N M=M\) show that \(M=0 .\) [Hint: Observe that the proof of Nakayama's lemma still holds. \(]\)
4 step solution
Problem 5
(a) Let \(J\) be a two-sided nilpotent ideal of \(R\). Show that \(J\) is contained in the radical. (b) Conversely, assume that \(R\) is Artinian. Show that its radical is nilpotent, i.e.. that there exists an integer \(r \geqslant 1\) such that \(N^{r}=0 .\) [Hint: Consider the descending sequence of powers \(N^{r}\), and apply Nakayama to a minimal finitely generated left ideal \(L \subset N^{*}\) such that \(N^{*} L+0\).
2 step solution
Problem 6
Let \(R\) be a semisimple commutative ring. Show that \(R\) is a direct product of fields.
6 step solution
Problem 7
Let \(R\) be a finite dimensional commutative algebra over a field \(k\). If \(R\) has no nilpotent element \(\neq 0\), show that \(R\) is semisimple.
4 step solution
Problem 8
(Kolchin) Let \(E\) be a finite-dimensional vector space over a field \(k\). Let \(G\) be a subgroup of \(G L(E)\) such that every element \(A \in G\) is of type \(I+N\) where \(N\) is nilpotent. Assume \(E \neq 0 .\) Show that there exists an element \(v \in E, v \neq 0\) such that \(A v=v\) for all \(A \in G .\) [Hint: First reduce the question to the case when \(k\) is algebraically closed by showing that the problem amounts to solving linear equations. Secondly, reduce it to the case when \(E\) is a simple \(k[G]\) -module. Combining Burnside's theorem with the fact that \(\operatorname{tr}(A)=\operatorname{tr}(I)\) for all \(A \in G\), show that if \(A_{0} \in G, A_{0}=I+N\), then \(\operatorname{tr}(N X)=0\) for all \(X \in\) End \(_{k}(E)\), and hence that \(\left.N=0, A_{0}=I .\right]\)
3 step solution
Problem 9
Let \(E\) be a finite dimensional vector space over a field \(k .\) Let \(R\) be a semisimple subalgebra of End \(_{4}(E)\). Let \(a, b \in R\). Assume that Ker \(b_{E} \supset\) Ker \(a_{E}\). where \(b_{E}\) is multiplication by \(b\) on \(E\) and similarly for \(a_{K}\). Show that there exists an element \(s \in R\) such that \(s a=b\). [Hint: Reduce to \(R\) simple. Then \(R=\) End \(_{D}\left(E_{0}\right)\) and \(E=E_{0}^{(\pi)} .\) Let \(v_{1}, \ldots, v, \in E\) be a \(D\) -basis for \(a E\). Define \(s\) by \(s\left(a v_{i}\right)=b v_{i}\) and extend s by D-linearity. Then \(s a_{E}=b_{\varepsilon}\), so \(\left.s a=b .\right]\)
5 step solution
Problem 10
Let \(E\) be a finite-dimensional vector space over a field \(k\). Let \(A \in\) End \(_{1}(E)\). We say that \(A\) is semisimple if \(E\) is a semisimple \(A\) -space, or equivalently, let \(R\) be the \(k\) -algebra generated by \(A\), then \(E\) is semisimple over \(R .\) Show that \(A\) is semisimple if and only if its minimal polynomial has no factors of multiplicity \(>1\) over \(k\).
2 step solution
Problem 11
Let \(E\) be a finite-dimensional vector space over a field \(k\), and let \(S\) be a commutative set of endomorphisms of \(E\). Let \(R=k[S]\). Assume that \(R\) is semisimple. Show that every subset of \(S\) is semisimple.
2 step solution
Problem 12
Prove that an \(R\) -module \(E\) is a generator if and only if it is balanced, and finitely generated projective over \(R^{\prime}(E) .\) Show that Theorem \(5.4\) is a consequence of Theorem 7.1.
6 step solution
Problem 13
Let \(A\) be a principal ring with quotient field \(K .\) Let \(A^{n}\) be \(n\) -space over \(A\), and let $$ T=A^{*} \oplus A^{n} \oplus \cdots \oplus A^{n} $$ be the direct sum of \(A^{n}\) with itself \(r\) times. Then \(T\) is free of rank \(n r\) over \(A\). If we view elements of \(A^{n}\) as column vectors, then \(T\) is the space of \(n \times r\) matrices over \(A\). Let \(M=\) Mat \(_{n}(A)\) be the ring of \(n \times n\) matrices over \(A\), operating on the left of \(T\). By a lattice \(L\) in \(T\) we mean an \(A\) -submodule of rank \(n r\) over \(A\). Prove that any such lattice which is \(M\) -stable is \(M\) -isomorphic to \(T\) itself. Thus there is just one \(M\) -isomorphism class of lattices. [Hint: Let \(g \in M\) be the matrix with 1 in the upper left corner and 0 everywhere else, so \(g\) is a projection of \(A^{\prime \prime}\) on a 1 -dimensional subspace. Then multiplication on the left \(g: T \rightarrow A_{r}\) maps \(T\) on the space of \(n \times r\) matrices with arbitrary first row and 0 everywhere else. Furthermore, for any lattice \(L\) in \(T\) the image \(g L\) is a lattice in \(A_{r}\), that is a free \(A\) -submodule of rank \(r\). By elementary divisors there exists an \(r \times r\) matrix \(Q\) such that \(g L=A, Q \quad\) (multiplication on the right). Then show that \(T Q=L\) and that multiplication by \(Q\) on the right is an \(M\) -isomorphism of \(T\) with \(L\) ]
6 step solution
Problem 14
Let \(F\) be a field. Let \(\mathrm{n}=\mathrm{n}(F)\) be the vector space of strictly upper triangular \(n \times n\) matrices over \(F\). Show that \(n\) is actually an algebra, and all elements of \(n\) are nilpotent (some positive integral power is 0 ).
5 step solution
Problem 15
Conjugation representation. Let \(A\) be the multiplicative group of diagonal
matrices in \(F\) with non-zero diagonal components. For \(a \in A\), the
conjugation action of \(a\) on \(\operatorname{Mat}_{n}(F)\) is denoted by
\(\mathrm{c}(a)\), so \(\mathrm{c}(a) M=a M a^{-1}\) for \(M \in
\mathrm{Mat}_{n}(F) .\) (a) Show that it
is stable under this action. (b) Show that \(n\) is semisimple under this
action. More precisely, for \(1 \leqq i
3 step solution