Chapter 4
A Gentle Introduction to the Art of Mathematics · 23 exercises
Problem 1
Let \(A=\\{1,2,4,5\\}, B=\\{2,3,4,6\\},\) and \(C=\\{1,2,3,4\\} .\) Place each of the elements \(1, \ldots, 6\) in the appropriate regions of a three-set Venn diagram.
8 step solution
Problem 1
Let \(A=\\{1,2,\\{1,2\\}, b\\}\) and let \(B=\\{a, b,\\{1,2\\}\\}\). Find the following: (a) \(A \cap B\) (b) \(A \cup B\) (c) \(A \backslash B\) (d) \(B \backslash A\) (e) \(A \triangle B\)
6 step solution
Problem 1
Insert either \(\in\) or \(\subseteq\) in the blanks in the following sentences (in order to produce true sentences). i) \(1 \)__________ \(\longrightarrow\\{3,2,1,\\{a, b\\}\\}\) ii) \(\\{a\\}\) __________ \(\\{a,\\{a, b\\}\\}\) iii) \(\\{a, b\\}\) __________ \(\\{3,2,1,\\{a, b\\}\\}\) iv) \(\\{\\{a, b\\}\\}\)__________ \(-\\{a,\\{a, b\\}\\}\)
5 step solution
Problem 1
What is the power set of \(\emptyset ?\) Hint: if you got the last exercise in the chapter you'd know that this power set has \(2^{0}=1\) element.
4 step solution
Problem 2
One way out of Russell's paradox is to declare that the collection of sets that don't contain themselves as elements is not a set itself. Explain how this circumvents the paradox.
4 step solution
Problem 2
Prove or disprove: $$(A \cap C \subseteq B \cap C) \quad \Longrightarrow \quad A \subseteq B$$.
6 step solution
Problem 2
Try iterating the power set operator. What is \(\mathcal{P}(\mathcal{P}(\emptyset)) ?\) What is \(\mathcal{P}(\mathcal{P}(\mathcal{P}(\emptyset))) ?\)
4 step solution
Problem 3
Venn diagrams are usually made using simple closed curves with no further restrictions. Try creating Venn diagrams for 3,4 and 5 sets (in general position) using rectangular simple closed curves.
4 step solution
Problem 3
Provide a counterexample to dispel the notion that a subset must have fewer elements than its superset.
4 step solution
Problem 3
Determine the following cardinalities. (a) \(A=\\{1,2,\\{3,4,5\\}\\} \quad|A|=\) __________ (b) \(B=\\{\\{1,2,3,4,5\\}\\} \quad|B|=\) __________
3 step solution
Problem 4
We have seen that \(A \subseteq B\) corresponds to \(M_{A} \Longrightarrow M_{B}\). What corresponds to the contrapositive statement?
4 step solution
Problem 5
For each positive integer \(n,\) we'll define an interval \(I_{n}\) by $$I_{n}=[-n, 1 / n)$$ Find the union and intersection of all the intervals in this infinite family. $$\begin{array}{l} \bigcup_{n \in \mathbb{N}} I_{n}= \\ \bigcap_{n \in \mathbb{N}} I_{n}= \end{array}$$
3 step solution
Problem 5
Determine two sets \(A\) and \(B\) such that both of the sentences \(A \in B\) and \(A \subseteq B\) are true.
4 step solution
Problem 6
Find the disjunctive normal form of \(A \cap(B \cup C)\).
3 step solution
Problem 6
There is a set \(X\) such that, for all sets \(A,\) we have \(X \Delta A=A .\) What is \(X ?\)
4 step solution
Problem 6
Prove that the set of perfect fourth powers is contained in the set of perfect squares.
5 step solution
Problem 7
Find the disjunctive normal form of \((A \triangle B) \triangle C\).
6 step solution
Problem 7
Find a logical open sentence such that \(\\{0,1,4,9, \ldots\\}\) is its truth set.
3 step solution
Problem 8
The prototypes for the modus ponens and modus tollens argument forms are the following: All men are mortal. Socrates is a man. Therefore Socrates is mortal. and All men are mortal. Zeus is not mortal. Therefore Zeus is not a \(\operatorname{man}\). Illustrate these arguments using Venn diagrams.
4 step solution
Problem 9
Use Venn diagrams to convince yourself of the validity of the following containment statement $$(A \cap B) \cup(C \cap D) \subseteq(A \cup C) \cap(B \cup D)$$ Now prove it!
6 step solution
Problem 9
Prove that \(A \cup(B \cap C)=(A \cup B) \cap(A \cup C)\) by showing that \(A \cup(B \cap C) \subseteq\) \((A \cup B) \cap(A \cup C)\) and \((A \cup B) \cap(A \cup C) \subseteq A \cup(B \cap C)\).
3 step solution
Problem 9
How many 8 element subsets are there in $$ \mathcal{P}(\\{a, b, c, d, e, f, g, h, i, j, k, l, m, n, o, p\\}) ? $$
5 step solution
Problem 10
Use Venn diagrams to show that the following set equivalence is false. $$(A \cup B) \cap(C \cup D)=(A \cup C) \cap(B \cup D).$$
6 step solution