Chapter 6
Complex Analysis for Mathematics and Engineering ยท 49 exercises
Problem 1
Recall that \(C_{\rho}^{+}\left(z_{0}\right)\) denotes the positively oriented circle \(\left\\{z:\left|z-z_{0}\right|=\rho\right\\}\). Find \(\int_{C_{1}^{+}(0)}(\exp z+\cos z) z^{-1} d z\)
5 step solution
Problem 1
Factor each polynomial as a product of linear factors. (a) \(P(z)=a^{4}+4\) (b) \(P(z)=z^{2}+(1+i) z+5 i\) (c) \(P(z)=x^{4}-4 z^{3}+6 z^{2}-4 z+5\) (d) \(P(z)=z^{3}-(3+3 i) z^{2}+(-1+6 i) z+3-i\). Hint: Show that \(P(i)=0\).
4 step solution
Problem 2
Let \(m\) and \(n\) be integers. Show that \(\int_{0}^{2 \pi} e^{i m t} e^{-i n t} d t=\left\\{\begin{array}{l}0 \text { when } m \neq n \\ 2 \pi \text { when } m=n\end{array}\right.\)
4 step solution
Problem 2
Sketch the following curves. (a) \(z(t)=t^{2}-1+i(t+4)\), for \(1 \leq t \leq 3\) (b) \(z(t)=\sin t+i \cos 2 t\), for \(-\frac{\pi}{2} \leq t \leq \frac{\pi}{2}\). (c) \(z(t)=5 \cos t-i 3 \sin t\), for \(\frac{\pi}{2} \leq t \leq 2 \pi\).
4 step solution
Problem 2
Show that \(\int_{C} z^{-1} d z=2 \pi i\), where \(C\) is the square with vertices \(1 \pm i\) and \(-1 \pm i\) and having positive orientation.
4 step solution
Problem 2
Recall that \(C_{\rho}^{+}\left(z_{0}\right)\) denotes the positively oriented circle \(\left\\{z:\left|z-z_{0}\right|=\rho\right\\}\). Find \(\int_{C_{1}^{+}(1)}(z+1)^{-1}(z-1)^{-1} d z\)
4 step solution
Problem 3
Show that \(\int_{0}^{\infty} e^{-z t} d t=\frac{1}{4}\) provided \(\operatorname{Re}(z)>0 .\)
5 step solution
Problem 3
Consider the integral \(\int_{C} z^{2} d z\), where \(C\) is the positively oriented upper semicircle of radius 1 , centered at 0 . (a) Give a Riemann sum approximation for the integral by selecting \(n=4\) and the points \(z_{k}=e^{i \frac{k}{4}}(k=0, \ldots, 4)\) and \(c_{k}=e^{i \frac{(2 k-1) \tau}{8}}(k=1, \ldots, 4)\). (b) Compute the integral exactly by selecting a parametrization for \(C\) and applying Theorem 6.1.
5 step solution
Problem 3
Show that \(\int_{C_{1}^{+}(0)}\left(4 z^{2}-4 z+5\right)^{-1} d z=0\).
4 step solution
Problem 3
Recall that \(C_{\rho}^{+}\left(z_{0}\right)\) denotes the positively oriented circle \(\left\\{z:\left|z-z_{0}\right|=\rho\right\\}\). Find \(\int_{C_{1}^{+}(1)}(z+1)^{-1}(z-1)^{-2} d z\)
6 step solution
Problem 3
Show that \(\cos z\) is not a bounded function.
4 step solution
Problem 4
Find \(\int_{C}\left(z^{2}-z\right)^{-1} d z\) for (a) circle \(C=C_{2}^{+}(1)=\\{z:|z-1|=2\\}\) having positive orientation. (b) circle \(C=C_{j}^{+}(1)=\left\\{z:|z-1|=\frac{1}{2}\right\\}\) having positive orientation.
5 step solution
Problem 4
Recall that \(C_{\rho}^{+}\left(z_{0}\right)\) denotes the positively oriented circle \(\left\\{z:\left|z-z_{0}\right|=\rho\right\\}\). Find \(\int_{C_{1}^{+}(1)}\left(z^{3}-1\right)^{-1} d z\)
4 step solution
Problem 4
Let \(f(z)=z^{2}\). Evaluate the following, where \(R\) represents the rectangular region defined by the set \(R=\\{z=x+i y: 2 \leq x \leq 3\) and \(1 \leq y \leq 3\\}\). (a) \(\max _{x \in R}|f(z)|\). (b) \(\left.\min _{x \in R} \mid f(z)\right]\). (c) \(\max _{x \in R} \operatorname{Re}[f(z)]\). (d) \(\left.\min _{z \in R} \operatorname{lm} \mid f(z)\right]\).
8 step solution
Problem 5
Let \(f(t)=u(t)+i v(t)\), where \(u\) and \(v\) are differentiable. Show that \(\int_{a}^{b} f(t) f^{\prime}(t) d t=\frac{1}{2}[f(b)]^{2}-\frac{1}{2}[f(a)]^{2} .\)
7 step solution
Problem 5
Find \(\int_{c}(2 z-1)\left(z^{2}-z\right)^{-1} d z\) for the (a) circle \(C=C_{2}^{+}(0)=\\{z:|z|=2\\}\) having positive orientation. (b) circle \(C=C_{j}^{+}(0)=\left\\{z:|z|=\frac{1}{2}\right\\}\) having positive orientation.
8 step solution
Problem 5
Recall that \(C_{\rho}^{+}\left(z_{0}\right)\) denotes the positively oriented circle \(\left\\{z:\left|z-z_{0}\right|=\rho\right\\}\). Find \(\int_{C_{1}^{+}(0)} z^{-4} \sin z d z\)
5 step solution
Problem 6
Recall that \(C_{\rho}^{+}\left(z_{0}\right)\) denotes the positively oriented circle \(\left\\{z:\left|z-z_{0}\right|=\rho\right\\}\). Find \(\int_{C_{1}^{+}(0)}(z \cos z)^{-1} d z\)
5 step solution
Problem 6
Let \(f\) be an entire function such that \(|f(z)| \leq M|z|\) for all \(z\). (a) Show that, for \(n \geq 2, f^{(n)}(z)=0\) for all \(z\). (b) Use part (a) to show that \(f(z)=a z+b\).
2 step solution
Problem 7
Recall \(C_{r}^{+}(a)\) is the circle of radius \(r\) centered at \(a\), oriented eounterclockwise. (a) Evaluate \(\int_{C_{i}^{+}(0)} z d z\). (b) Evaluate \(\int_{\sigma_{4}^{+}(0)} \bar{y} d z\). (c) Evaluate \(\int_{C_{2}^{-}(0)} \frac{1}{x} d z\). (The minus sign means elockwise orientation.) (d) Evaluate \(\int_{C_{2}^{-}(0)} \frac{1}{2} d z\). (e) Evaluate \(\int_{C}(z+1) d z\), where \(C\) is \(C_{1}^{+}(0)\) in the first quadrant. (f) Evaluate \(\int_{c}\left(x^{2}-i y^{2}\right) d z\), where \(C\) is the upper half of \(C_{1}^{+}(0)\). (g) Evaluate \(\int_{C}|z-1|^{2} d z\), where \(C\) is the upper half of \(C_{1}^{+}(0)\).
7 step solution
Problem 7
Evaluate \(\int_{C}\left(4 z^{2}+4 z-3\right)^{-1} d z=\int_{C}(2 z-1)^{-1}(2 z+3)^{-1} d z\) for (a) the circle \(C=C_{1}^{+}(0)\). (b) the circle \(C=C_{1}^{+}\left(-\frac{2}{3}\right)=\left\\{z:\left|z+\frac{2}{3}\right|=1\right\\}\). (c) the circle \(C=C_{3}^{+}(0)\).
4 step solution
Problem 7
Establish the following minimum modulus principle. (a) Let \(f\) be analytie and nonconstant in the domain \(D .\) If \(|f(z)| \geq m\) for all \(z\) in \(D\), where \(m>0\), then \(|f(z)|\) does not attain a minimum value at any point \(z_{0}\) in \(D\). (b) Show that the requirement \(m>0\) in part a is necessary by finding an example of a function defined on \(D\) for which \(m=0\), and yet whose minimum is attained somewhere in \(D\).
4 step solution
Problem 8
Use Green's theorem to show that the area enclosed by a simple closed contour \(C\) is \(\frac{1}{2} \int_{C} x d y-y d x\).
6 step solution
Problem 8
Let \(u(x, y)\) be harmonic for all \((x, y)\). Show that $$ u\left(x_{0}, y_{0}\right)=\frac{1}{2 \pi} \int_{0}^{2 \pi} u\left(x_{0}+R \cos \theta, y_{0}+R \sin \theta\right) d \theta $$ where \(R>0 .\) Hint: Let \(f(z)=u(x, y)+i v(x, y)\), where \(v\) is a harmonic conjugate of \(u\).
5 step solution
Problem 9
Establish the following maximum principle for harmonic functions. Let \(u(x, y)\) be harmonic and nonconstant in the simply connected domain \(D\). Then u does not have a maximum value at any point \(\left(x_{0}, y_{0}\right)\) in \(D\).
4 step solution
Problem 10
Find \(\int_{C} z^{-2}\left(z^{2}-16\right)^{-1} \exp z d z\) along the following contours: (a) The circle \(C_{1}^{+}(0)\). (b) The circle \(C_{1}^{+}(4)\).
3 step solution
Problem 10
Let \(f\) be an entire function with the property that \(|f(z)| \geq 1\) for all \(z\). Show that \(f\) is constant.
5 step solution
Problem 11
Evaluate \(\int_{C} z^{2} d z\), where \(C\) is the line segment from 1 to \(1+i\).
7 step solution
Problem 11
Let \(f\) be a nonconstant analytic function in the closed disk \(\bar{D}_{1}(0)\). Suppose that \(|f(z)|=K\) for \(z \in C_{1}(0)\). Show that \(f\) has a zero in \(D\). Hint: Use both the maximum and minimum modulus principles.
4 step solution
Problem 12
Evaluate \(\int_{C}\left|z^{2}\right| d z\), where \(C\) is given by \(C: z(t)=t+i t^{2}\), for \(0 \leq t \leq 1\).
6 step solution
Problem 12
Suppose that \(f(z)=u(r, \theta)+i v(r, \theta)\) is analytic for all values of \(z=r e^{i \theta}\). Show that \(\int_{0}^{2 \pi}[u(r, \theta) \cos \theta-v(r, \theta) \sin \theta] d \theta=0\) Hint: Integrate \(f\) around the circle \(C_{1}^{+}(0)\).
8 step solution
Problem 12
Find \(\int_{C} z^{-1}(z-1)^{-1} \exp z d z\) along the following contours: (a) The circle \(C_{j}^{+}(0)\). (b) The circle \(C_{2}^{+}(0)\).
5 step solution
Problem 12
Why is it important to study the fundamental theorem of algebra in a complex analysis course?
5 step solution
Problem 13
Evaluate \(\int_{C} \exp z \mathrm{~d} s\), where \(C\) is the straight-line segment joining 1 to \(1+i \pi\).
7 step solution
Problem 14
Evaluate \(\int_{C}^{z} \exp z d z\), where \(C\) is the square with vertices \(0,1,1+i\), and \(i\) taken with the counterclock wise orientation.
3 step solution
Problem 14
Find \(\int_{C_{3}^{+}(1)}\left(z^{2}+1\right)^{-2} d z\).
4 step solution
Problem 15
Evaluate \(\int_{C} \exp z d z\), where \(C\) is the straight-line segment joining 0 to \(1+i\).
9 step solution
Problem 15
Show that \(\int_{C} 1 d z=z_{2}-z_{1}\), where \(C\) is the line segment from \(z_{1}\) to \(z_{2}\), by parametrizing \(C .\)
6 step solution
Problem 16
Let \(z(t)=x(t)+i y(t)\), for \(a \leq t \leq b\), be a smooth curve. Give a meaning for each of the following expressions. (a) \(z^{\prime}(t)\). (b) \(\left|z^{\prime}(t)\right| d t\). (c) \(\int_{a}^{b} z^{\prime}(t) d t\) (d) \(\int_{a}^{b}\left|z^{\prime}(t)\right| d t\)
4 step solution
Problem 16
Let \(P(z)=a_{0}+a_{1} z+a_{2} z^{2}+a_{3} z^{3}\). Find \(\int_{C_{1}^{+}(0)} P(z) z^{-n} d z\), where \(n\) is a positive integer.
6 step solution
Problem 17
Evaluate \(\int_{0} \cos z d z\), where \(C\) is the polygonal path from 0 to \(1+i\) that consists of the line segments from 0 to 1 and 1 to \(1+i\).
9 step solution
Problem 17
Let \(I_{1}\) and \(z_{2}\) be two complex numbers that lie interior to the simple closed contour \(C\) with positive orientation. Evaluate \(\int_{C}\left(z-z_{1}\right)^{-1}\left(z-z_{2}\right)^{-1} d z\).
6 step solution
Problem 18
Let \(f(t)=e^{i t}\) be defined on \(a \leq t \leq b\), where \(a=0\), and \(b=2 \pi .\) Show that there is no number \(c \in(a, b)\) such that \(f(c)(b-a)=\int_{0}^{b} f(t) d t .\) In other words, the mean value theorem for definite integrals that you learned in ealculus does not hold for complex funetions.
5 step solution
Problem 18
Using partial fraction decomposition, show that if \(z\) lies in the right half- plane and \(C\) is the line segment joining 0 to \(z\), then $$ \int_{C} \frac{d \xi}{\xi^{2}+1}=\operatorname{Arctan} z=\frac{i}{2} \log (z+i)-\frac{i}{2} \log (z-i)+\frac{\pi}{2} $$
6 step solution
Problem 18
Let \(f\) be analytic in the simply connected domain \(D\) and let \(z_{1}\) and \(z_{2}\) be two complex numbers that lie interior to the simple closed contour \(C\) having positive orientation that lies in \(D\). Show that, \(\frac{f\left(z_{2}\right)-f\left(z_{1}\right)}{z_{2}-z_{1}}=\frac{1}{2 \pi i} \int_{C} \frac{f(z) d z}{\left(z-z_{1}\right)\left(z-z_{2}\right)}\) State what happens when \(z_{2} \rightarrow z_{1}\).
6 step solution
Problem 19
Use the ML inequality to show that \(\left|P_{n}(x)\right| \leq 1\), where \(P_{n}\) is the nth Legendre polynomial defined on \(-1 \leq x \leq 1\) by \(P_{n}(x)=\frac{1}{x} \int_{0}^{\pi}\left(x+i \sqrt{1-x^{2}} \cos \theta\right)^{n} d \theta\).
5 step solution
Problem 19
Let \(f^{\prime}\) and \(g^{\prime}\) be analytic for all \(z\) and let \(C\) be any contour joining the points \(z_{1}\) and \(z_{2}\). Show that $$ \int_{C} f(z) g^{\prime}(z) d z=f\left(z_{2}\right) g\left(z_{2}\right)-f\left(z_{1}\right) g\left(z_{1}\right)-\int_{C} f^{\prime}(z) g(z) d z $$
5 step solution
Problem 19
The Legendre polynomial \(P_{n}(z)\) is defined by \(P_{n}(z)=\frac{1}{2^{n} n !} \frac{d^{n}}{d z^{n}}\left[\left(z^{2}-1\right)^{n}\right]\) Use Cauchy's integral formula to show that \(P_{n}(z)=\frac{1}{2 \pi i} \int_{C} \frac{\left(\xi^{2}-1\right)^{n} d \xi}{2^{n}(\xi-z)^{n+1}}\) where \(C\) is a simple closed contour having positive orientation and \(z\) lies inside \(C\).
4 step solution
Problem 20
Explain how contour integrals in complex analysis and line integrals in calculus are different. How are they similar?
5 step solution