Chapter 6

A Course in Calculus and Real Analysis · 44 exercises

Problem 2

Let \(f:[0,1] \rightarrow \mathbb{R}\) be given by $$ f(x):=\left\\{\begin{array}{ll} 1+x & \text { if } x \text { is rational } \\ 0 & \text { if } x \text { is irrational } \end{array}\right. $$ Is \(f\) integrable?

5 step solution

Problem 3

Let \(f:[a, b] \rightarrow \mathbb{R}\) be integrable. Show that the Riemann integral of \(f\) is the unique real number \(r\) satisfying the following condition: For every \(\epsilon>0\), there is a partition \(P_{e}\) of \([a, b]\) such that $$ r-\epsilon

4 step solution

Problem 4

Let \(f:[0,3] \rightarrow \mathbb{R}\) be defined by $$ f(x):=\left\\{\begin{array}{ll} 0 & \text { if } 0 \leq x \leq 1 \\ 2 & \text { if } 1

2 step solution

Problem 5

Let \(f, g:[a, b] \rightarrow \mathbb{R}\) be bounded functions. Show that $$ L(f)+L(g) \leq L(f+g) \quad \text { and } \quad U(f+g) \leq U(f)+U(g) $$ Hence conclude that if \(f\) and \(g\) are integrable, then so is \(f+g\), and the Riemann integral of \(f+g\) is equal to the sum of the Riemann integrals of \(f\) and \(g\).

4 step solution

Problem 7

Let \(f:[a, b] \rightarrow \mathbb{R}\) be a function. Show that \(f\) is integrable if (i) \(r f\) is integrable for some nonzero \(r \in \mathbb{R}\), or (ii) if \(f\) is bounded, \(f(x) \neq 0\) for all \(x \in[a, b]\), and \(1 / f\) is integrable.

2 step solution

Problem 8

Let \(f:[a, b] \rightarrow \mathbb{R}\) be any function. Suppose there is \(r \in \mathbb{R}\) and for each \(n \in \mathbb{N}\), there are integrable functions \(g_{n}, h_{n}:[a, b] \rightarrow \mathbb{R}\) with \(g_{n} \leq f \leq h_{n}\) such that \(\int_{a}^{b} g_{n}(x) d x \rightarrow r\) and \(\int_{a}^{b} h_{n}(x) d x \rightarrow r\) as \(n \rightarrow \infty\). Show that \(f\) is integrable and the Riemann integral of \(f\) is equal to \(r\).

5 step solution

Problem 9

Let \(f:[a, b] \rightarrow \mathbb{R}\) be integrable and \(f(x) \geq 0\) for all \(x \in[a, b] .\) Show that \(\int_{a}^{b} f(x) d x \geq 0 .\) If, in addition, \(f\) is continuous and \(\int_{a}^{b} f(x) d x=0\), then show that \(f(x)=0\) for all \(x \in[a, b] .\) Give an example of an integrable function on \([a, b]\) such that \(f(x) \geq 0\) for all \(x \in[a, b]\) and \(\int_{a}^{b} f(x) d x=0\) but \(f(x) \neq 0\) for some \(x \in[a, b]\).

3 step solution

Problem 10

Evaluate the following limits. (i) \(\lim _{h \rightarrow 0} \frac{1}{h} \int_{x}^{x+h} \frac{d u}{u+\sqrt{u^{2}+1}}\), (ii) \(\lim _{x \rightarrow 0} \frac{1}{x^{3}} \int_{0}^{x} \frac{t^{2} d t}{t^{4}+1}\) (iii) \(\lim _{x \rightarrow 0} \frac{1}{x^{6}} \int_{0}^{x^{2}} \frac{t^{2} d t}{t^{6}+1}\), (iv) \(\lim _{x \rightarrow x_{0}} \frac{x}{x-x_{0}} \int_{x_{0}}^{x} f(t) d t\), (v) \(\lim _{x \rightarrow x_{0}} \frac{x}{x^{2}-x_{0}^{2}} \int_{x_{0}}^{x} f(t) d t\), provided \(f\) is continuous at \(x_{0}\).

6 step solution

Problem 11

Let \(a, b, c \in \mathbb{R}\) with \(a

9 step solution

Problem 12

Let \(n \in \mathbb{N}\). Find a function \(f:[-1,1] \rightarrow \mathbb{R}\) for which \(f^{(n)}(0)\) exists, but \(f^{(n+1)}(0)\) does not. (Hint: Begin with the absolute value function and use part (ii) of Proposition \(6.22\) repeatedly.)

4 step solution

Problem 14

Let \(f:[a, b] \rightarrow \mathbb{R}\) be integrable and let \(F:[a, b] \rightarrow \mathbb{R}\) be given by \(F(x):=\) \(\int_{a}^{x} f(t) d t\) for \(x \in[a, b] .\) If \(f\) is nonnegative on \([a, b]\), then show that \(F\) is monotonically increasing on \([a, b] .\) Also, if \(f\) is monotonically increasing on \([a, b]\), then show that \(F\) is convex on \([a, b] .\) (Hint: To prove the convexity of \(F\), note that \(\left(F(x)-F\left(x_{1}\right)\right) /\left(x-x_{1}\right) \leq f(x) \leq\left(F\left(x_{2}\right)-F(x)\right) /\left(x_{2}-x\right)\) whenever \(a \leq x_{1}

2 step solution

Problem 15

Let \(f:[a, \infty) \rightarrow \mathbb{R}\) be a bounded function that is integrable on \([a, x]\) for every \(x \geq a\). Let \(F(x):=\int_{a}^{x} f(t) d t\) for \(x \geq a\). Show that \(F\) satisfies a Lipschitz condition on \([a, \infty)\), and so \(F\) is uniformly continuous on \([a, \infty)\).

5 step solution

Problem 16

Let \(f:[0, \infty) \rightarrow \mathbb{R}\) be continuous and \(f(x) \geq 0\) for all \(x \in[0, \infty)\). If for each \(b>0\), the area bounded by the \(x\) -axis, the lines \(x=0, x=b\), and the curve \(y=f(x)\) is given by \(\sqrt{b^{2}+1}-1\), determine the function \(f\).

4 step solution

Problem 17

Let \(p\) be a real number and let \(f: \mathbb{R} \rightarrow \mathbb{R}\) be a continuous function such that \(f(x+p)=f(x)\) for all \(x \in \mathbb{R}\). (Such a function is said to be periodic.) Show that the integral \(\int_{a}^{a+p} f(t) d t\) has the same value for every real number \(a\). (Hint: Part (i) of Proposition 6.24.)

5 step solution

Problem 18

Let \(f:[a, b] \rightarrow \mathbb{R}\) be continuous. Show that for every \(x \in[a, b]\), $$ \int_{a}^{x}\left(\int_{a}^{u} f(t) d t\right) d u=\int_{a}^{x}(x-u) f(u) d u $$

4 step solution

Problem 19

Let \(f:[a, b] \rightarrow \mathbb{R}\) be integrable. Define \(F:[a, b] \rightarrow \mathbb{R}\) by $$ F(x):=\int_{x}^{b} f(t) d t \quad \text { for } x \in[a, b] $$ Show that \(F\) is continuous on \([a, b]\). Further, show that if \(f\) is continuous at \(c \in[a, b]\), then \(F\) is differentiable at \(c\) and \(F^{\prime}(c)=-f(c)\). (Hint: Propositions 6.8, 6.22, and 6.24.)

2 step solution

Problem 20

Let \(g:[c, d] \rightarrow \mathbb{R}\) be such that \(g([c, d]) \subseteq[a, b]\), and let \(f:[a, b] \rightarrow \mathbb{R}\) be integrable. Define \(F:[c, d] \rightarrow \mathbb{R}\) by $$ F(y):=\int_{a}^{g(y)} f(t) d t \quad \text { for } y \in[c, d] $$ If \(g\) is differentiable at \(y_{0} \in[c, d]\) and \(f\) is continuous at \(g\left(y_{0}\right)\), then show that \(F\) is differentiable at \(y_{0}\) and \(F^{\prime}\left(y_{0}\right)=f\left(g\left(y_{0}\right)\right) g^{\prime}\left(y_{0}\right)\).

6 step solution

Problem 21

Let \(f, g:[a, b] \rightarrow \mathbb{R}\) be such that \(f\) is differentiable, \(f^{\prime}\) is integrable, and \(g\) is continuous. If $$ G(x):=\int_{a}^{x} g(t) d t \quad \text { and } \quad \tilde{G}(x):=\int_{x}^{b} g(t) d t \quad \text { for } x \in[a, b] $$ then show that $$ \int_{a}^{b} f(x) g(x) d x=f(b) G(b)-\int_{a}^{b} f^{\prime}(x) G(x) d x=f(a) \widetilde{G}(a)+\int_{a}^{b} f^{\prime}(x) \widetilde{G}(x) d x $$ (Compare Proposition 6.28.)

4 step solution

Problem 22

(Leibniz Rule for Integrals) Let \(f\) be a continuous function on \([a, b]\) and let \(u, v\) be differentiable functions on \([c, d] .\) If the ranges of \(u\) and \(v\) are contained in \([a, b]\), prove that $$ \frac{d}{d x} \int_{u(x)}^{v(x)} f(t) d t=f(v(x)) \frac{d v}{d x}-f(u(x)) \frac{d u}{d x} $$

5 step solution

Problem 23

For \(x \in \mathbb{R}\), let \(F(x):=\int_{1}^{2 x} \frac{1}{1+t^{2}} d t\) and \(G(x):=\int_{0}^{x^{2}} \frac{1}{1+\sqrt{t}} d t\). Find \(F^{\prime}\) and \(G^{\prime}\).

4 step solution

Problem 25

Let \(n, m \in \mathbb{N}\). Find \(\lim _{m \rightarrow \infty} \int_{0}^{1} \frac{x^{n}}{(1+x)^{m}} d x\) and \(\lim _{n \rightarrow \infty} \int_{0}^{1} \frac{x^{n}}{(1+x)^{m}} d x\).

6 step solution

Problem 26

Find \(\lim _{n \rightarrow \infty} \int_{0}^{1} \frac{n x^{n-1}}{1+x} d x .\) (Hint: Proposition 6.28.)

4 step solution

Problem 27

Let \(f:[a, b] \rightarrow \mathbb{R}\) be a differentiable function. If \(F\) is an antiderivative of \(f\) on \([a, b]\), then show that $$ \int_{a}^{b} f^{2}(x) d x=F(b) F^{\prime}(b)-F(a) F^{\prime}(a)-\int_{a}^{b} F(x) F^{\prime \prime}(x) d x $$

4 step solution

Problem 29

Let \(f:[a, b] \rightarrow \mathbb{R}\) be a differentiable function such that \(f^{\prime}\) is continuous on \([a, b]\) and \(f^{\prime}(x) \neq 0\) for all \(x \in[a, b]\). If \(f([a, b])=[c, d]\), then show that \(f^{-1}:[c, d] \rightarrow \mathbb{R}\) is integrable and $$ \int_{c}^{d} f^{-1}(y) d y=f^{-1}(d) d-f^{-1}(c) c-\int_{f^{-1}(c)}^{f^{-1}(d)} f(x) d x $$ (Hint: Propositions \(6.28\) and \(6.29 .\) )

2 step solution

Problem 30

Let \(f:[a, b] \rightarrow \mathbb{R}\) be a bounded function and define \(g:[-b,-a] \rightarrow \mathbb{R}\) by \(g(t):=f(-t) .\) Show that \(L(g)=L(f)\) and \(U(g)=U(f) .\) Deduce that \(g\) is integrable on \([-b,-a]\) if and only if \(f\) is integrable on \([a, b]\) and in that case the Riemann integral of \(g\) is equal to the Riemann integral of \(f\).

3 step solution

Problem 31

Assuming that \(f\) is integrable on \([0,1]\), show that $$ \lim _{n \rightarrow \infty} \frac{1}{n}\left(f\left(\frac{1}{n}\right)+f\left(\frac{2}{n}\right)+\cdots+f\left(\frac{n}{n}\right)\right)=\int_{0}^{1} f(x) d x $$

3 step solution

Problem 33

Do \(\lim _{n \rightarrow \infty} \sum_{i=1}^{n} \frac{1}{\sqrt{i+n}}\) and \(\lim _{n \rightarrow \infty} \frac{1}{n^{18}} \sum_{i=1}^{n} i^{16}\) exist? If yes, find them.

7 step solution

Problem 34

Find an approximate value of \(1^{1 / 3}+2^{1 / 3}+\cdots+1000^{1 / 3}\).

5 step solution

Problem 36

Let \(a, b \in \mathbb{R}\) with \(0 \leq a

4 step solution

Problem 37

Domain Additivity of Lower/Upper Riemann Integrals) Suppose \(f:[a, b] \rightarrow \mathbb{R}\) is a bounded function. For \(c \in(a, b)\), let \(f_{1}\) and \(f_{2}\) denote the restrictions of \(f\) to the subintervals \([a, c]\) and \([c, b] .\) Prove that \(L(f)=\) \(L\left(f_{1}\right)+L\left(f_{2}\right)\) and \(U(f)=U\left(f_{1}\right)+U\left(f_{2}\right) .\) (Compare Proposition 6.8.)

4 step solution

Problem 38

Let \(f:[a, b] \rightarrow \mathbb{R}\) be integrable and let \(g:[m(f), M(f)] \rightarrow \mathbb{R}\) be continuous. Show that \(g \circ f:[a, b] \rightarrow \mathbb{R}\) is integrable. (Hint: Given \(\epsilon>0\), find \(\delta>0\) using the uniform continuity of \(g .\) There is a partition \(P\) of \([a, b]\) such that \(U(P, f)-L(P, f)<\delta^{2}\). Divide the summands in \(U(P, f)-L(P, f)\) into two parts depending on whether or not \(M_{i}(f)-m_{i}(f)<\delta .\) Use the Riemann condition for \(g \circ f .\) )

6 step solution

Problem 39

Let \(f_{1}, \ldots, f_{m}:[a, b] \rightarrow \mathbb{R}\) be integrable functions and let \(r_{j}:=\int_{a}^{b} f_{j}(x) d x\) for \(j=1, \ldots, m .\) Show that the function \(\sqrt{f_{1}^{2}+\cdots+f_{m}^{2}}\) is integrable and $$ \sqrt{r_{1}^{2}+\cdots+r_{m}^{2}} \leq \int_{a}^{b} \sqrt{f_{1}^{2}(x)+\cdots+f_{m}^{2}(x)} d x $$ (Hint: Note that \(\sum_{j=1}^{m} r_{j}^{2}=\sum_{j=1}^{m} r_{j} \int_{a}^{b} f_{j}(x) d x=\int_{a}^{b}\left(\sum_{j=1}^{m} r_{j} f_{j}(x)\right) d x\) and use Proposition 1.12.)

3 step solution

Problem 40

Let \(m, n \in \mathbb{Z}\) with \(m, n \geq 0\). Show that $$ \int_{0}^{1} x^{m}(1-x)^{n} d x=\frac{m ! n !}{(m+n+1) !} . $$ (Hint: If \(n \in \mathbb{N}\) and \(I_{m, n}\) denotes the given integral, then using Integration by Parts, \(I_{m, n}=(n /(m+1)) I_{m+1, n-1}\), and \(I_{m+n, 0}=1 /(m+n+1) .\) )

3 step solution

Problem 41

Let \(a \in \mathbb{R}\) and \(n \in \mathbb{Z}\) with \(n \geq 0 .\) Show that $$ \int_{0}^{a}\left(a^{2}-x^{2}\right)^{n} d x=\frac{\left(2^{n} n !\right)^{2}}{(2 n+1) !} \cdot a^{2 n+1} $$ Deduce that $$ 1-\frac{1}{3}\left(\begin{array}{l} n \\ 1 \end{array}\right)+\frac{1}{5}\left(\begin{array}{l} n \\ 2 \end{array}\right)-\frac{1}{7}\left(\begin{array}{l} n \\ 3 \end{array}\right)+\cdots+\frac{(-1)^{n}}{2 n+1}\left(\begin{array}{l} n \\ n \end{array}\right)=\frac{\left(2^{n} n !\right)^{2}}{(2 n+1) !} $$ (Hint: For \(n \geq 0\), let \(I_{n}\) denote the given integral. Then \(I_{0}=a\) and \(I_{n}=a^{2} I_{n-1}-\int_{0}^{a} x g_{n}(x) d x\), where \(g_{n}(x):=x\left(a^{2}-x^{2}\right)^{n-1}\) for \(n \in \mathbb{N} .\) Use Integration by Parts to obtain \(I_{n}=2 n a^{2} I_{n-1} /(2 n+1)\) for \(n \in \mathbb{N} .\) )

3 step solution

Problem 42

(Taylor Theorem with Integral Remainder) Let \(n\) be a nonnegative integer and let \(f:[a, b] \rightarrow \mathbb{R}\) be such that \(f^{\prime}, f^{\prime \prime}, \ldots, f^{(n)}\) exist on \([a, b]\) and further, \(f^{(n)}\) is continuously differentiable on \([a, b] .\) Show that $$ f(b)=f(a)+f^{\prime}(a)(b-a)+\cdots+\frac{f^{(n)}(a)}{n !}(b-a)^{n}+\frac{1}{n !} \int_{a}^{b}(b-t)^{n} f^{(n+1)}(t) d t $$ Further, show that the integral remainder is equal to $$ \frac{(b-a)^{n+1}}{n !} \int_{0}^{1}(1-s)^{n} f^{(n+1)}(a+s(b-a)) d s $$ and that there is \(c \in[a, b]\) such that the integral remainder is equal to $$ \frac{f^{(n+1)}(c)}{(n+1) !}(b-a)^{n+1} $$ (Hint: Induction on \(n\), Integration by Parts, and IVP of \(f^{(n+1)}\) ) [Note: Unlike the Lagrange form of the remainder, the integral remainder does not involve an undetermined number \(c \in(a, b) .]\)

6 step solution

Problem 43

(Taylor Theorem for Integrals) Let \(n \in \mathbb{N}\) and \(f:[a, b] \rightarrow \mathbb{R}\) be such that \(f^{\prime}, f^{\prime \prime}, \ldots, f^{(n-1)}\) exist on \([a, b]\), and further, \(f^{(n-1)}\) is continuous on \([a, b]\) and differentiable on \((a, b) .\) Show that there is \(c \in(a, b)\) such that \(\int_{a}^{b} f(x) d x=f(a)(b-a)+\cdots+\frac{f^{(n-1)}(a)}{n !}(b-a)^{n}+\frac{f^{(n)}(c)}{(n+1) !}(b-a)^{n+1}\) (Hint: For \(x \in[a, b]\), define \(F(x):=\int_{a}^{x} f(t) d t\) and apply Proposition \(\left.4.25 .\right)\)

3 step solution

Problem 44

Let \(f:[a, b] \rightarrow \mathbb{R}\) be integrable. If \(\phi:[\alpha, \beta] \rightarrow \mathbb{R}\) is a differentiable function such that \(\phi^{\prime}\) is integrable on \([\alpha, \beta]\), and \(\phi^{\prime}(t) \neq 0\) for every \(t \in(\alpha, \beta)\), then show that the function \((f \circ \phi)\left|\phi^{\prime}\right|:[\alpha, \beta] \rightarrow \mathbb{R}\) is integrable and $$ \int_{a}^{b} f(x) d x=\int_{\alpha}^{\beta} f(\phi(t))\left|\phi^{\prime}(t)\right| d t . $$ (Hint: Either \(\phi^{\prime}>0\) or \(\phi^{\prime}<0\) on \((\alpha, \beta)\). Let \(\psi:=(f \circ \phi)|\phi|\) and let \(\epsilon>0\) be given. For any partition \(P\) of \([a, b]\), obtain a partition \(Q\) of \([\alpha, \beta]\) with \(L(P, f)

6 step solution

Problem 45

(Bliss Theorem) Let \(f, g:[a, b] \rightarrow \mathbb{R}\) be any functions. For each \(n \in \mathbb{N}\), consider a partition \(P_{n}:=\left\\{x_{n, 0}, x_{n, 1}, \ldots, x_{n, k_{n}}\right\\}\) of \([a, b]\), and for \(i=\) \(1, \ldots, k_{n}\), let \(s_{n, i}, t_{n, i} \in\left[x_{n, i-1}, x_{n, i}\right]\), and let $$ \widetilde{S}_{n}:=\sum_{i=1}^{k_{n}} f\left(s_{n, i}\right) g\left(t_{n, i}\right)\left(x_{n, i}-x_{n, i-1}\right) . $$ Show that if \(f\) is integrable, \(g\) is continuous, and \(\mu\left(P_{n}\right) \rightarrow 0\), then $$ \tilde{S}_{n} \rightarrow \int_{a}^{b} f(x) g(x) d x $$ (Hint: If \(\mathcal{T}_{n}:=\left\\{s_{n, i}: i=1, \ldots, k_{n}\right\\}\), then \(S\left(P_{n}, \mathcal{T}_{n}, f g\right) \rightarrow \int_{a}^{b} f(x) g(x) d x\) Also, \(g\) is uniformly continuous.)

4 step solution

Problem 46

Let \(f:[a, b] \rightarrow \mathbb{R}\) be a monotonic function. If \(G:[a, b] \rightarrow \mathbb{R}\) is differentiable and \(G^{\prime}\) is continuous, then show that there is \(c \in[a, b]\) such that $$ \int_{a}^{b} f(x) G^{\prime}(x) d x=f(b) G(b)-f(a) G(a)-G(c)(f(b)-f(a)) $$ (Hint: Given any partition \(P=\left\\{x_{0}, x_{1}, \ldots, x_{n}\right\\}\) of \([a, b]\), consider the \(\operatorname{sum} \sum_{i=1}^{n} f\left(x_{i}\right)\left(G\left(x_{i}\right)-G\left(x_{i-1}\right)\right)\). Write it as \(f(b) G(b)-f(a) G(a)-\) \(\sum_{i=1}^{n} G\left(x_{i-1}\right)\left(f\left(x_{i}\right)-f\left(x_{i-1}\right)\right)\) and also as \(\sum_{i=1}^{n} f\left(x_{i}\right) G^{\prime}\left(s_{i}\right)\left(x_{i}-x_{i-1}\right)\) for some \(s_{i} \in\left[x_{i-1}, x_{i}\right] .\) Use Exercise \(6.45\) and note \(m(g)(f(b)-f(a)) \leq\) \(\left.\sum_{i=1}^{n} G\left(x_{i-1}\right)\left(f\left(x_{i}\right)-f\left(x_{i-1}\right)\right) \leq M(g)(f(b)-f(a)) .\right)\)

5 step solution

Problem 47

(First Mean Value Theorem for Integrals) Let \(f:[a, b] \rightarrow \mathbb{R}\) be a continuous function and let \(g:[a, b] \rightarrow \mathbb{R}\) be a nonnegative integrable function. Use the IVP of \(f\) to show that there is \(c \in[a, b]\) such that $$ \int_{a}^{b} f(x) g(x) d x=f(c) \int_{a}^{b} g(x) d x $$ Give examples to show that neither the continuity of \(f\) nor the nonnegativity of \(g\) can be omitted. [Note: For another version of this result, see Exercise \(8.72 .\) ]

3 step solution

Problem 48

(Second Mean Value Theorem for Integrals) Let \(f:[a, b] \rightarrow \mathbb{R}\) be a monotonic function and let \(g:[a, b] \rightarrow \mathbb{R}\) be either a nonnegative integrable function or a continuous function. Show that there is \(c \in[a, b]\) such that $$ \int_{a}^{b} f(x) g(x) d x=f(a) \int_{a}^{c} g(x) d x+f(b) \int_{c}^{b} g(x) d x $$ Give an example to show that the monotonicity of \(f\) cannot be omitted. (Hint: Without loss of generality, suppose \(f\) is (monotonically) increasing. Let \(G(x):=\int_{a}^{x} g(t) d t\) for \(x \in[a, b] .\) If \(g\) is a nonnegative integrable function, then \(f(a) G(b) \leq \int_{a}^{b} f(x) g(x) d x \leq f(b) G(b)\). If \(g\) is continuous, use Exercise 6.46.)

5 step solution

Problem 49

(Cauchy Condition) Let \(f:[a, b] \rightarrow \mathbb{R}\) be a bounded function. Show that \(f\) is integrable on \([a, b]\) if and only if for every \(\epsilon>0\), there is a partition \(P\) of \([a, b]\) such that for all tag sets \(\mathcal{T}\) and \(\mathcal{T}^{\prime}\) associated with \(P\), $$ \left|S(P, \mathcal{T}, f)-S\left(P, \mathcal{T}^{\prime}, f\right)\right|<\epsilon $$ (Hint: Argue as in the proof of Proposition 6.36.)

2 step solution

Problem 50

Let \(E\) be a bounded subset of \(\mathbb{R}\) and let \(\partial E\) denote the boundary of \(E\). (i) Show that if \(E\) is of content zero, then \(\bar{E}:=E \cup \partial E\) is of content zero. (ii) Show that \(E\) is of content zero if and only if \(E\) has no interior points and \(\partial E\) is of content zero.

3 step solution

Problem 51

Let \(f:[a, b] \rightarrow \mathbb{R}\) be integrable, and let \(g:[a, b] \rightarrow \mathbb{R}\) be a bounded function such that the set \(\\{x \in[a, b]: g(x) \neq f(x)\\}\) is of content zero. Show that \(g\) is integrable and $$ \int_{a}^{b} g(x) d x=\int_{a}^{b} f(x) d x $$ (Compare Proposition 6.13.)

3 step solution

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