Chapter 4
Chemistry in 30 days · 24 exercises
Problem 4
Heat of neutralization of an acid with a base is \(13.7 \mathrm{kcal}\) when (a) both acid and base are weak (b) acid is weak and base is strong (c) acid is strong and base is weak (d) both acid and base are strong
4 step solution
Problem 5
The calorific value of fat is (a) less than that of carbohydrates and protein (b) less than that of protein but more than carbohydrates (c) less than that of carbohydrates but more than that of protein (d) more than that of carbohydrate and protein
3 step solution
Problem 7
In which case, a spontaneous reaction is possible at any temperature ? (a) \(\Delta H-v e, \Delta \bar{S}+v e\) (b) \(\Delta H-v e, \Delta S-v e\) (c) \(\Delta H+\) ve, \(\Delta S+v e\) (d) none of the cases
3 step solution
Problem 8
The work done by a system is \(8 \mathrm{~J}\), when \(40 \mathrm{~J}\) heat is supplied to it. The change in internal energy of the system during the process: (a) \(32 \mathrm{~J}\) (b) \(40 \mathrm{~J}\) (c) \(36 \mathrm{~J}\) (d) \(44 \mathrm{~J}\)
4 step solution
Problem 9
The factor that does not influence the heat of reaction is (a) The physical state of reactants and products (b) The temperature (c) The pressure or volume (d) The method by which the final products are obtained
6 step solution
Problem 10
When \(10 \mathrm{ml}\) of \(0.1 \mathrm{M}\) soln. of \(\mathrm{HCl}\) is mixed with \(10 \mathrm{ml}\) of \(0.1 \mathrm{M}\) of \(\mathrm{KOH}\) solution, the rise in temperature was observed to be \(4^{\circ} \mathrm{C}\). If \(100 \mathrm{ml}\) of \(0.1 \mathrm{M} \mathrm{HCl}\) and \(100 \mathrm{ml}\) of \(0.1 \mathrm{M} \mathrm{KOH}\) are mixed in the same vessel, the rise in temperature would be (a) \(40^{\circ} \mathrm{C}\) (b) \(4^{\circ} \mathrm{C}\) (c) \(20^{\circ}\) (d) unpredictable
6 step solution
Problem 11
An example of extensive property is (a) temperature (b) internal energy (c) viscosity (d) surface tension
3 step solution
Problem 12
The enthalpy of neutralisation of \(\mathrm{NaOH}\) with \(\mathrm{HCl}\) is \(57.1 \mathrm{~kJ}\), while with \(\mathrm{CH}_{3} \mathrm{COOH}\), it is \(-55 \mathrm{~kJ}\). This happens because (a) Acetic acid is an organic acid (b) Acetic acid is little soluble in water (c) Acetic acid is a weak acid and requires lesser sodium hydroxide for neutralisation (d) Some heat is required to ionize acetic acid completely
4 step solution
Problem 13
On the basis of information available from the reaction \(\frac{4}{3} \mathrm{Al}+\mathrm{O}_{2} \rightarrow \frac{2}{3} \mathrm{Al}_{2} \mathrm{O}_{3}: \Delta G=-827 \mathrm{~kJ} \mathrm{~mol}^{-1}\) of \(\mathrm{O}_{2}\), the minimum emf required to carry out electrolysis of \(\mathrm{Al}_{2} \mathrm{O}_{3}\) is \(\left(F=96500 \mathrm{C} \mathrm{mol}^{-1}\right)\) (a) \(8.56 \mathrm{~V}\) (b) \(2.14 \mathrm{~V}\) (c) \(4.28 \mathrm{~V}\) (d) \(6.42 \mathrm{~V}\)
5 step solution
Problem 14
In a chemical reaction \(\Delta H=150 \mathrm{~kJ}\) and \(\Delta S=100 \mathrm{JK}^{-1}\) at \(300 \mathrm{~K}\). the \(\Delta G\) for the reaction is: (a) Zero (b) \(300 \mathrm{~kJ}\) (c) \(330 \mathrm{~kJ}\) (d) \(120 \mathrm{~kJ}\)
6 step solution
Problem 15
In which case, a spontaneous reaction is impossible at any temperature? (a) \(\Delta H+v e, \Delta S+v e\) (b) \(\Delta H+\mathrm{ve}, \Delta S\)-ve (c) \(\Delta H-v e, \Delta S-\) ve (d) In all cases
5 step solution
Problem 17
On combustion carbon forms two oxides \(\mathrm{CO}\) and \(\mathrm{CO}_{2}\). heat of formation of \(\mathrm{CO}_{2}\) is \(-94.3\) kcal and that of \(\mathrm{CO}\) is \(-26.0 \mathrm{kcal}\). Heat of combustion of carbon is (a) \(-26.0 \mathrm{kcal}\) (b) \(-68.3 \mathrm{kcal}\) (c) \(-94.3 \mathrm{kcal}\) (d) \(-120.3 \mathrm{kcal}\)
4 step solution
Problem 18
The heat of formation of \(\mathrm{MgO}, \mathrm{Al}_{2} \mathrm{O}_{3}\) and \(\mathrm{SiO}_{2}\) are \(-602,-1676\) and, \(-911 \mathrm{~kJ} \mathrm{~mol}^{-1}\), respectively, Most stable oxide is (a) \(\mathrm{MgO}\) (b) \(\mathrm{Al}_{2} \mathrm{O}_{3}\) \(\begin{array}{ll}\text { (c) } \mathrm{SiO}_{2} & \text { (d) Cannot be predicted } \\ \text { enfoge }\end{array}\)
4 step solution
Problem 19
The molar enthalpy of fusion of water is \(6.01 \mathrm{~kJ} \mathrm{~mol}^{-1}\). The entharps change of \(1 \mathrm{~mol}\) of water at its melting point will be (a) \(22 \mathrm{~kJ} \mathrm{~mol}^{-1}\) (b) \(109 \mathrm{~kJ} \mathrm{~mol}^{-1}\) (c) \(44 \mathrm{~kJ} \mathrm{~mol}^{-1}\) (d) \(11 \mathrm{~kJ} \mathrm{~mol}^{-1}\)
4 step solution
Problem 20
The heat of neutralisation of strong base and strong acid is \(57.0 \mathrm{~kJ}\); the heat released when \(0.5 \mathrm{~mol}\) of \(\mathrm{HNO}_{3}\) solution is added to \(0.20 \mathrm{~mol}\) of \(\mathrm{NaOH}\) solution is (a) \(57.0 \mathrm{~kJ}\) (b) \(28.5 \mathrm{~kJ}\) (c) \(11.40 \mathrm{~kJ}\) (d) \(34.9 \mathrm{~kJ}\)
5 step solution
Problem 21
An endothermic reaction is spontaneous if
(a) \(\Delta H>T \Delta S\)
(b) \(\Delta H
4 step solution
Problem 25
If an endothermic reaction is non-spontaneous at freezing point of water and becomes feasible at its boiling point, then (a) \(\Delta H\) is \(-v e, \Delta S\) is \(+\) ve (b) \(\Delta H\) and \(\Delta S\) both are +ve (c) \(\Delta H\) and \(\triangle S\) both are -ve (d) \(\Delta H\) is \(+\mathrm{ve}, \Delta S\) is \(-\mathrm{ve}\)
4 step solution
Problem 26
Assuming that water vapour is an ideal gas, the internal energy change \((\Delta U)\) when 1 mol of water is vapourized at 1 bar pressure and \(100^{\circ} \mathrm{C}\), will be: (Given molar enthalpy of vapourization of water at 1 bar and \(373 \mathrm{~K}=41 \mathrm{~kJ} \mathrm{~mol}^{-1}\) and \(R=8.3 \mathrm{JK}^{-1} \mathrm{~mol}^{-1}\) ) (a) \(41.00 \mathrm{~kJ} \mathrm{~mol}^{-1}\) (b) \(4.100 \mathrm{~kJ} \mathrm{~mol}^{-1}\) (c) \(3.7904 \mathrm{~kJ} \mathrm{~mol}^{-1}\) (d) \(37.904 \mathrm{~kJ} \mathrm{~mol}^{-1}\)
6 step solution
Problem 27
The enthalpy and entropy changes for the reaction \(\mathrm{Br}_{2}(1)+\mathrm{Cl}_{2}(\mathrm{~g}) \rightleftharpoons 2 \mathrm{BrCl}(\mathrm{g})\) are \(30 \mathrm{~kJ} \mathrm{~mol}^{-1}\) and \(105 \mathrm{~J} \mathrm{~K}^{-1} \mathrm{~mol}^{-1}\), respectively. The temperature at which the reaction will be in equilibrium is (a) \(285.7 \mathrm{~K}\) (b) \(273 \mathrm{~K}\) (c) \(450 \mathrm{~K}\) (d) \(300 \mathrm{~K}\)
5 step solution
Problem 29
Given that bond energies of \(\mathrm{H}-\mathrm{H}\) and \(\mathrm{Cl}-\mathrm{Cl}\) are \(430 \mathrm{~kJ} / \mathrm{mol}\) and \(240 \mathrm{~kJ} / \mathrm{mol}\), respectively. \(\Delta H_{f}\) for \(\mathrm{HCl}\) is \(-90 \mathrm{~kJ} / \mathrm{mol}\). Bond enthalpy of \(\mathrm{HCl}\) is (a) \(380 \mathrm{~kJ} \mathrm{~mol}^{-1}\) (b) \(425 \mathrm{~kJ} \mathrm{~mol}^{-1}\) (c) \(245 \mathrm{~kJ} \mathrm{~mol}^{-1}\) (d) \(290 \mathrm{~kJ} \mathrm{~mol}^{-1}\)
5 step solution
Problem 31
The enthalpy of combustion of cyclohexane, cyclohexene and \(\mathrm{H}_{2}\) are respectively \(-3920,-3800\) and \(-241 \mathrm{~kJ} \mathrm{~mol}^{-1}\). The heat of hydrogenation of cyclohexene is (a) \(-121 \mathrm{~kJ} \mathrm{~mol}^{-1}\) (b) \(+121 \mathrm{~kJ} \mathrm{~mol}^{-1}\) (c) \(-242 \mathrm{~kJ} \mathrm{~mol}^{-1}\) (d) \(+242 \mathrm{~kJ} \mathrm{~mol}^{-1}\)
5 step solution
Problem 32
In the conversion of lime stone to lime, \(\mathrm{CaCO}_{3}(\mathrm{~s}) \rightarrow \mathrm{CaO}(\mathrm{s})+\mathrm{CO}_{2}(\mathrm{~g})\) The values of \(\Delta H^{\circ}\) and \(\Delta S^{\circ}\) are \(+179.1 \mathrm{~kJ} \mathrm{~mol}^{-1}\) and \(160.2 \mathrm{JK}^{-1} \mathrm{~mol}^{-1}\), respectively at 298 \(\mathrm{K}\) and 1 bar. Assuming that \(\Delta H^{\circ}\) and \(\Delta S^{\circ}\) do not change with temperature; temperature above which conversion of lime stone to lime will be spontaneous is (a) \(1118 \mathrm{~K}\) (b) \(1008 \mathrm{~K}\) (c) \(1200 \mathrm{~K}\) (d) \(845 \mathrm{~K}\)
5 step solution
Problem 33
The amount of heat measured for a reaction in a bomb calorimeter is (a) \(\Delta G\) (b) \(\Delta H\) (c) \(\Delta E\) (d) \(P \Delta V\)
3 step solution
Problem 34
Calculate the enthalpy change for the following: \(400 \mathrm{ml}\) of \(0.2 \mathrm{M} \mathrm{H}_{2} \mathrm{SO}_{4}\) added to \(300 \mathrm{ml}\) of \(0.1 \mathrm{M} \mathrm{KOH}\). (a) \(-3.43 \mathrm{~kJ}\) (b) \(-1.71 \mathrm{~kJ}\) (c) \(-6.86 \mathrm{~kJ}\) (d) \(-10.29 \mathrm{~kJ}\)
4 step solution