Chapter 27

Chemistry in 30 days · 20 exercises

Problem 1

The isocyanide test is used for the detection of (a) Primary alcohols (b) Primary amines (c) Secondary amines (d) Secondary alcohols

3 step solution

Problem 2

Primary amines on being heated with \(\mathrm{CS}_{2}\) in the presence of \(\mathrm{HgCl}_{2}\) form alkyl/ary! isothiocyanates. The reaction is known as (a) Hofmann hypobromite reaction (b) Hofmann climination reaction (c) Hofmann-Martius reaction (d) Hofmann mustard oil reaction

3 step solution

Problem 3

Benzoylation reaction in aqueous medium is known as (a) Claisen reaction (b) Schotten Baumann reaction (c) Perkin reaction (d) Reformatsky reaction

3 step solution

Problem 4

Benzenediazonium chloride on reaction with phenol in weakly basic medium gives (a) diphenyl ether (b) \(p\)-hydroxyazobenzene (c) chlorobenzene (d) benzene

4 step solution

Problem 7

The IUPAC name of the tertiary amine formed by the reaction of methylamine with ethyl bromide is (a) \(\mathrm{N}\), \(\mathrm{N}\)-dimethylethanamine (b) \(\mathrm{N}\), N-diethylmethanamine (c) N-ethyl-N-methylethanamine (d) \(\mathrm{N}, \mathrm{N}\)-diethylaminomethane

4 step solution

Problem 8

Which of the following is most basic in gas phase? (a) \(\mathrm{NH}_{3}\) (b) \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{NH}_{2}\) (c) \(\left(\mathrm{CH}_{3} \mathrm{CH}_{2}\right)_{2} \mathrm{NH}\) (d) \(\left(\mathrm{CH}_{3} \mathrm{CH}_{2}\right)_{3} \mathrm{~N}\)

4 step solution

Problem 10

Among the following compounds, the one which will produce 1-phenylethanamine in Hofmann hypobromite reaction is (a) 2-phenylpropanamide (b) 3 -phenylpropanamide (c) 2-phenylethanamide (d) \(\mathrm{N}\)-phenylethanamide

4 step solution

Problem 11

Eithylamine can be prepared by the action of \(\mathrm{Br}_{2}\) and \(\mathrm{NaOH}\) solution on (a) Acetamide (b) Propionamide(c) Formamide (d) Methyl cyanide

3 step solution

Problem 13

Amongat the following the most basic compound is (a) Benzylamine (b) Aniline (c) Acetanilide (d) \(p\)-nitroaniline

4 step solution

Problem 14

In the \(\left(\mathrm{CH}_{1}\right)_{3} \mathrm{~N}\) molecule, the hybridization state of the nitrogen atom and the spatial arrangement of the methyl groups around it are respectively (a) \(s p^{3}\), tetrahedral (b) sp' pyramidal (c) \(s p^{2}\), trigonal planar (d) sp", trigonal planar

4 step solution

Problem 16

Amine-N-oxide on heating forms alkene. The reaction is called (a) Hofmann elimination (b) Saytref elimination (c) Cope elimination (d) Peterson elimination

4 step solution

Problem 17

The primary amine can be distinguished from a secondary amine by using (a) \(\mathrm{Br}_{2}\) and \(\mathrm{KOH}\) (b) \(\mathrm{HClO}\) (c) \(\mathrm{HNO}_{2}\) (d) \(\mathrm{NH}_{3}\)

6 step solution

Problem 19

Best method for preparing \(1^{\circ}\) amines from alkyl halides is by (a) Hofmann bromamide reaction (b) Gabriel phthalimide reaction (c) Both are equally good (d) Reaction with \(\mathrm{NH}_{3}\)

6 step solution

Problem 20

Which of the following is least basic? (a) \(\mathrm{FCH}_{2} \mathrm{CH}_{2} \mathrm{NH}_{2}\) (b) \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{NH}_{2}\) (c) \(\mathrm{ClCH}_{2} \mathrm{CH}_{2} \mathrm{NH}_{2}\) (d) All are equally basic

4 step solution

Problem 21

A compound A has a molecular formula \(\mathrm{C}_{7} \mathrm{H}_{7} \mathrm{NO} .\) On treatment with \(\mathrm{Br}_{2}\) and \(\mathrm{KOH}\), A gives an amine \(B\) which gives carbylamine test. B upon diazotisation and coupling with phenol gives an azo dye. \(\mathrm{A}\) can be (a) \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CONHCOCH}_{3}\) (b) \(\mathrm{C}_{6} \mathrm{H}_{3} \mathrm{CONH}_{2}\) (c) \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{NO}_{2}\) (d) \(0, \mathrm{~m}\) - or \(\mathrm{p}-\mathrm{C}_{6} \mathrm{H}_{4}\left(\mathrm{NH}_{2}\right) \mathrm{CHO}\)

5 step solution

Problem 23

Aniline is reacted with bromine water and the resulting produet is treated with an aqueous solution of sodium nitrite in presence of dilute HC1. The compound so formed is converted into tetrafluoroborate which is subsequently heated dry. The final product is (a) \(p\) - Ifromefluorobenzene (b) \(p\)-Bromoaniline (e) 2, 4, 6-Tribromofluorobenzene (d) \(1,3,5\)-Tribromobenzene

4 step solution

Problem 24

Butanenitrile may be prepared by heating (a) Propyl alcohol with \(\mathrm{KCN}\) (b) Butyl alcohol with KCN (c) Butyl chloride with KCN (d) Propyl chloride with \(\mathrm{KCN}\)

3 step solution

Problem 25

Benzamide on reaction with \(\mathrm{POCl}_{3}\) gives (a) Aniline (b) Chlorobenzene (c) Benzyl amine (d) Benzonitrile

4 step solution

Problem 29

\(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{Cl} \stackrel{\mathrm{NaCN}}{\longrightarrow} \mathrm{X} \stackrel{\mathrm{Ni} / \mathrm{H}_{2}}{\longrightarrow} \mathrm{Y} \stackrel{\text { acetic anhydride }}{\longrightarrow} \mathrm{Z}\) Z. in the above reaction sequence is (a) \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{NHCOCH}_{3}\) (b) \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{NH}_{2}\) (c) \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CONHCH}_{3}\) (d) \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CONHCOCH}_{3}\)

3 step solution

Problem 32

The most basic compound amongst the following is (a) Benzylamine (b) Aniline (c) \(p\)-Nitroaniline (d) Ethanamide

3 step solution

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