Chapter 24

\(6.9 \mathrm{mL}\) of \(6.0 \mathrm{M} \mathrm{NaOH}\) are diluted with water to a volume of \(400.0 \mathrm{mL}\). You are asked to find the molarity of the resulting solution. a. First find out how many moles of NaOH are present in \(6.9 \mathrm{mL}\) of \(6.0 \mathrm{M} \mathrm{NaOH}\). Use Equation 1. Note that the volume must be in liters. ___________moles b. Since the total number of moles of NaOH is not changed on dilution, the molarity after dilution can also be found by Equation 1 , using the final volume of the solution. Calculate that molarity. __________\(\mathbf{M}\)

In an acid-base titration, \(22.13 \mathrm{mL}\) of an NaOH solution are needed to neurralize \(22.44 \mathrm{mL}\) of a \(0.0997 \mathrm{M}\) HCI solution. To find the molarity of the NaOH solution, we can use the following procedure: a. First note the value of \(M_{\mathrm{H}}\) - in the HCI solution. ___________\(\mathbf{M}\) b. Find \(M_{\mathrm{ott}}\) - in the NaOH solution. (Use Eq. 3.) ___________ \(\mathbf{M}\) c. Obtain \(M_{\text {NaOH }}\) from \(M_{\text {OH }-}\) ______________\(\mathbf{M}\)