Question 1.27 - Chemistry: Molecular Nature Of Matter And Change

Question

The radius of a barium atom is $\mathbf{2}\mathbf{.}\mathbf{22}\mathbf{\times }{\mathbf{10}}^{\mathbf{-}\mathbf{2}}$m .What is its radius in angstrom $\left(°A\right)$?

Step-by-Step Solution

Answer

Answer

 

The radius of a barium atom in angstrom$\left(°A\right)$ is $\mathbf{2}\mathbf{.}\mathbf{22}\mathbf{ }\mathbf{°}\mathit{A}$  .

Conversion

Converting a given radius in meters to $\left(˚A\right)$

$$\begin{gathered} 1°A ={10}^{-10}m \\ \frac{1°A}{{10}^{-10}m} and \frac{{10}^{-10}m}{1°A} \end{gathered}$$

Calculation

$$\begin{gathered} Radius = Radius in m \times Conversion factor into °A \\ = 2.22\times {10}^{-10}m\times \left(\frac{1°A}{1\times {10}^{-10}m}\right) \\ =2.22 °A \end{gathered}$$

 

The radius of a barium atom in angstrom $\left(°A\right)$ is $\mathbf{2}\mathbf{.}\mathbf{22}\mathbf{ }\mathbf{°}\mathit{A}$  .