Q9PE - College Physics (Urone)

Question

Find the frequency of a tuning fork that takes 2.50 x 10^-3 s to complete one oscillation.

Step-by-Step Solution

Answer

The time taken by the turning fork is, T = 2.50 x 10^-3 s

Step 1: Identification of the given data

The time taken by the turning fork is, T = 2.50 x 10^-3 s

Step 2: Definition of time period

The defined period of time for which a particular event occurs at a specific rate is termed the time period. It can be determined by taking the inverse of the frequency and it is measured in terms of seconds.

Step 3: Determination of frequency

Write the expression for the frequency.

 

\(f = \frac{1}{T}\)

 

Here, \(T\) is the time period.

 

Substitute all the values in the above expression.

 

\(\begin{aligned}f &= \frac{1}{{2.50 \times {{10}^{ - 3}}\;{\rm{s}}}}\\ &= 400\;{{\rm{s}}^{ - 1}} \times \frac{{1\;{\rm{Hz}}}}{{{{\rm{s}}^{ - 1}}}}\\ &= 400\;{\rm{Hz}}\end{aligned}\)

 

Thus, the frequency is 400 Hz.