Q9E - University Physics with Modern Physics

Question

A certain fuel-efficient hybrid car gets gasoline mileage of 55.0 mpg (miles per gallon). (a) If you are driving this car in Europe and want to compare its mileage with that of other European cars, express this mileage in km/L 1L = liter2. Use the conversion factors in Appendix E. (b) If this car’s gas tank holds 45 L, how many tanks of gas will you use to drive 1500 km?

Step-by-Step Solution

Answer

Given-

Mileage of car is 55.0 mpg

The tank holds 45L of fuel

Step1- conversion which are required in solving this problem

We know that

1mi=1.609km

And 1gallon=3.785liters

Convert 55.0miles/gallon to kilometer /liters

55.0miles/gallon =55.0miles/gallon(1.609km/1mile)x(1gallon/3.785liters)

55.0miles/gallon=$\frac{\left(55.0\right)\left(1.609\right)}{3.785}km/L$

55.0miles/gallon=23.4km/L

Thus , the mileage is 23.4km/L

Step2(Calculation of capacity of tank)

From the mileage we know that distance is 23.4km for 1L

So for 1500km we need.

                                                     $$\begin{gathered} \frac{23.4kl}{45L}=\frac{1500km}{x} \\ X=\frac{1500km\left(1L\right)}{23.4km} \\ X=64.1L \end{gathered}$$

The car has a tank with capacity 45L.

Step 3( Calculation of number of tank required-)

Solve for number of tanks

                                                       $$\begin{gathered} \frac{1\tan k}{45L}=\frac{y}{64.1L} \\ y=\frac{\left(64.1\right)\left(1\tan k\right)}{45L} \\ y=1.42\tan ks \end{gathered}$$

Thus, tanks of gas used to cover 1500km is1.42tanks

Step 4-(Conclusion)-

After comparison with European car mileage is=23.4Km/L

Capacity of Tank is 45Liters

Number of Tanks used  1.42