Q.99

Question

What values of θ,f(θ)=sec(θ) does not exist

Step-by-Step Solution

Verified
Answer

the value for the function does not exist when θ=(2n+1)π2

1Step 1: Given information

We are given a function f(θ)=sec(θ)

2Step 2: Explanation

We have,

f(θ)=sec(θ)f(θ)=1cos(θ)

The function does not exist when cos(θ)=0θ=(2n+1)π2