Q.98 - Intermediate Algebra

Question

Use the Definition of a Negative Exponent

In the following exercises, simplify each expression.

$$\begin{gathered} \left(a\right)b^{-4} \\ \left(b\right){10}^{-2} \\ \left(c\right)\frac{1}{c^{-5}} \\ \left(d\right)\frac{1}{5^{-2}} \end{gathered}$$

Step-by-Step Solution

Answer

The simplified form of the expressions are:

$\begin{array}{rcl}\left(a\right)b^{-4}& =& \frac{1}{b^4}\\ \left(b\right){10}^{-2}& =& \frac{1}{{10}^2}\\ \left(c\right)\frac{1}{c^{-5}}& =& c^5\\ \left(d\right)\frac{1}{5^{-2}}& =& 5^2\end{array}$

Step 1

The properties of negative exponents:

$\begin{array}{rcl}{a}^{-n}& =& \frac{1}{a^n}\\ \frac{1}{a^{-n}}& =& a^n\end{array}$

Step 2

Use the negative property $a^{-n}=\frac{1}{a^n}$to simplify the expressions:

$\begin{array}{rcl}\left(a\right)b^{-4}& =& \frac{1}{b^4}\\ \left(b\right){10}^{-2}& =& \frac{1}{{10}^2}\end{array}$

Step 3

Use the negative property$\frac{1}{a^{-n}}=a^n$ to simplify the expressions:

$\begin{array}{rcl}\left(c\right)\frac{1}{c^{-5}}& =& c^5\\ \left(d\right)\frac{1}{5^{-2}}& =& 5^2\end{array}$