Q96P - Chemistry: Molecular Nature Of Matter And Change

Question

Give the name and formula for the acid derived from each of the following anions

1. hydrogen sulfate
2. ${\mathbf{lO}}_{\mathbf{3}}^{\mathbf{-}}$
   
3. cyanide
4. ${\mathbf{HS}}^{\mathbf{-}}$
   

Step-by-Step Solution

Answer

1. The acid derivative of hydrogen sulfate is${\mathbf{H}}_{\mathbf{2}}{\mathbf{SO}}_{\mathbf{4}}$ i.e., sulfuric acid.
2. The acid derivative of ${\mathbf{lO}}_{\mathbf{3}}$is${\mathbf{HlO}}_{\mathbf{3}}$.
3. The acid derivative of cyanide is$\mathbf{HCN}$.
4. The acid derivative of${\mathbf{HS}}^{\mathbf{-}}$ is${\mathbf{H}}_{\mathbf{2}}\mathbf{S}$.

Step 1: Acid derivative of hydrogen sulfate

Hydrogen sulfate has a formula${\mathbf{HSO}}_{\mathbf{4}}^{\mathbf{-}}$It has a charge of -1 so add 1 hydrogen to remove the charge. The acid derivative of hydrogen sulfate ${\mathbf{H}}_{\mathbf{2}}{\mathbf{SO}}_{\mathbf{4}}$isi.e., sulfuric acid.

Step 2: Acid derivative of IO 3 -

${\mathbf{lO}}_{\mathbf{3}}^{\mathbf{-}}$has a charge of -1, so adding one H⁺ ion charge will be nullified. Acid derivative of ${\mathbf{lO}}_{\mathbf{3}}^{\mathbf{-}}$is ${\mathbf{HlO}}_{\mathbf{3}}$.

Step 3: Acid derivative of cyanide

The formula of cyanide is${\mathbf{CN}}^{\mathbf{-}}$ It also has a charge of -1, so adding one H⁺ ion charge will be nullified. The acid derivative of cyanide is $\mathbf{HCN}$.

Step 4: Acid derivative of HS -

${\mathbf{HS}}^{\mathbf{-}}$has a charge of -1 so add 1 hydrogen to remove the charge. Acid derivative of${\mathbf{HS}}^{\mathbf{-}}$ is${\mathbf{H}}_{\mathbf{2}}\mathbf{s}$.