Q9.62P - Chemistry: Molecular Nature Of Matter And Change

Question

Use Figure 9.20, p. 364, to indicate the polarity of each bond with partial charges

(a) Br-Cl

(b) F-Cl

(c) H-O

(d) Se-H

(e) As-H

(f) S-N.

 

Step-by-Step Solution

Answer

 

Polarity is the division of electric charge into negatively and positively charged ends in a molecule or its chemical groups, which produces an electric dipole moment.

Step 1: Polarity and Electronegativity

As the difference in electronegativity widens, the electron distribution becomes more polarised and the partial charges of the atoms rise accordingly.

Step 2: Polarity of each bond with partial charges

(a) Br   $\mathbf{\to }$    Cl 

(b) F     $\leftarrow$    Cl 

(c) H    $\mathbf{\to }$     O 

(d) Se  $\mathbf{\to }$     H 

(e) As    $\mathbf{\to }$   H 

(f) S       $\mathbf{\to }$   N