Q9. - Algebra 1

Question

The table shows the costs of certain items at a corner hardware store.

a. Write two expressions to represent the total cost of 3 boxes of nails, 2 boxes of screws, 2 hammers, and 1 electric drill.

b. What is the total cost of the items purchased?

Step-by-Step Solution

Answer

1. The two expressions are $3\left(3.80\right)+2\left(5.25\right)+2\left(12.95\right)+43.50$ and $11.40+10.50+25.90+43.50$
2. The total cost of the item purchase is $91.30.

Part a. Step 1. Given Information.

We have given a table of item with their respective cost.

Item	Cost
Box of nails	$3.80
Box of screws	$5.25
Claw hammer	$12.95
Electric drill	$42.50

 

Part a. Step 2. Concept.

For finding the total cost, we have to multiply the item with their respective cost and then represent it into the addition format.

i.e.

We have to multiply the first column with the second column and write it into the addition format to get the total cost.

Part a. Step 3. Find the expression to represent the total cost.

The first expression is $3\left(3.80\right)+2\left(5.25\right)+2\left(12.95\right)+43.50$

The second expression is $11.40+10.50+25.90+43.50$

 

Therefore,

The two expressions are $3\left(3.80\right)+2\left(5.25\right)+2\left(12.95\right)+43.50$ and $11.40+10.50+25.90+43.50$

Part b. Step 1. Given information.

We have given a table of items with their respective cost.

Item	Cost
Box of nails	$3.80
Box of screws	$5.25
Claw hammer	$12.95
Electric drill	$42.50

 

Part b. Step 2. Concept.

For finding the total cost of the item purchased, we just have to add the above expression.

i.e.

The addition of the above expression gives the total cost.

Part b. Step 3. To find the total cost of the item purchased.

The total cost of the item purchased $=11.40+10.50+25.90+43.50=\$91.30$.

 

Therefore, the total cost of the item purchase is $91.30.