Q9 E

Question

Why is the concept of hybridization required in valence bond theory?

Step-by-Step Solution

Verified

Answer

Hybridization is necessary to determine the molecular geometry of complex.

1Step 1: Definition of Concept

Hybridization occurs when two or more different pure orbitals with comparable energy are mixed together to produce an equivalent amount of impure orbitals with equal energy and definite geometry, which are referred to as hybrid orbitals.

2Step 2: Explain why is the concept of hybridization required in valence bond theory

Hybridization: Hybrid orbitals are created when two or more different pure orbitals with comparable energy are mixed together to produce an equivalent amount of impure orbitals with equal energy and definite geometry. This phenomenon is known as hybridization. It uses the valence bond theory of orbitals to help determine molecular geometry.

Therefore, the molecular geometry of complexes must be determined through hybridization..

Q8 E

Q10 E

Other exercises in this chapter

Q7 E

A friend tells you \({{\rm{N}}_{\rm{2}}}\)has three \({\rm{\pi }}\)bonds due to overlap of the three p-orbitals on each N atom. Do you agree?

View solution

Q8 E

Draw the Lewis structures for \({\rm{C}}{{\rm{O}}_{\rm{2}}}\)and\({\rm{CO}}\), and predict the number of \({\rm{\sigma }}\) and \({\rm{\pi }}\) bonds for each m

View solution

Q10 E

Give the shape that describes each hybrid orbital set:(a) \({\rm{s}}{{\rm{p}}^{\rm{2}}}\)(b) \({\rm{s}}{{\rm{p}}^{\rm{3}}}{\rm{d}}\)(c) sp(d) \({\rm{s}}{{\rm{p}

View solution

Q12 E

What is the hybridization of the central atom in each of the following?(a) \({\rm{Be}}{{\rm{H}}_{\rm{2}}}\)(b) \({\rm{S}}{{\rm{F}}_{\rm{6}}}\)(c) \({\rm{PO}}_{\

View solution