Q8P

Question

(a) Prove that the two-dimensional rotation matrix (Eq.1.29) preserves dot products.
 (That is, show that AyBy¯+AzBz¯=AyBy+AzBz
.)
(b) What constraints must the elements (Rij ) of the three-dimensional rotation matrix
(Eq.1.30) satisfy, in order to preserve the length of A (for all vectors A )?

Step-by-Step Solution

Verified
Answer

(a)      It is proved that two dimensional rotation matrix preserves dot product

(b)     The constraints in order to preserve the length of A are:

 

2RxyRxz+RyyRyz+RzyRzz=02RxzRxx+RyzRyx+RzzRzx=02RxyRxz+RyyRyz+RzyRzz=02RxxRxy+RxyRyy+RzxRzy=0


And


Rxx2+Ryx2+Rzx2=0Rxy2+Ryy2+Rzy2=0Rxz2+Ryz2+Rzz2=0

1Step 1: Explain the concept and write the 2-D matix.

The scalars are invariant under rotations. Mass m is always the same under rotations.

Also, dot product is a scalar quantity. So, it should be invariant under rotation.  Vectors transformation of rotation around axis is given by,

 


Ay=cosϕAy+sinϕAzAz=-sinϕAy+cosϕAz

 

 

Similarly, find By and Bz

 


By=cosϕBy+sinϕBzBz=-sinϕBy+cosϕBz 

 

The dot product of two dimensional rotational vector


Hence, the two-dimensional rotation matrix preserves dot products.

2Step 2: Find the constraint on rotation matrix

Since the coordinate system is rotated around an arbitrary axis, Origin is always at the same point in both the coordinate system. So length of the vector should be invariant. Under rotation.

 

For rotation about an arbitrary axis in three dimensions, the transformation law is,

 

Ax¯Ay¯Az¯=RxxRxyRxzRyxRyyRxzRzxRzyRzzAxAyAz


Compare the length of the  system in the two coordinated system as follows:

 

Ax¯2+Ay¯2+Az¯2=Ax2+Ay2+Az2    Ax¯2+Ay¯2+Az¯2=Ax2+Ay2+Az2

 

Let us consider

Ax¯2=Rxx2Ax2+Rxy2Az2+2RxxRxyAxAy+2RxyRxzAyAz+2RxzRxxAzAx


Similarly, we can write 

 

Ay¯2=Ryy2Ax2+Rxy2Ay2+Rxz2Az2+2RxxRxyAxAy+2RxyRxzAyAz+2RxzRxxAzAxAz¯2=Rzz2Az2+Rzy2Ay2+Rzx2Ax2+2RzzRzyAzAy+2RzyRzxAyAz+2RzxRzzAzAy


So, 


Ax¯2+Ay¯2+Az¯2=Rxx2+Ryx2+Rzx2Ax2+Rxy2+Ryy2+Rzy2Ay2Rxz2+Ryz2+Rzz2Az2                               +RxxRxy+RxyRyy+RzxRzyAyAx+2RxyRxz+RyyRyz+RzyRzzAyAz                               +2RxyRxz+RyyRyz+RzyRzzAyAz+2RxzRxx+RyzRyx+RzzRzxAzAx 


On comparing this equation with equation (1), we get

 

2RxyRxz+RyyRyz+RzyRzz=02RxzRxx+RyzRyx+RzzRzx=02RxyRxz+RyyRyz+RzyRzz=02RxxRxy+RxyRyy+RzxRzy=0

 

And also, we obtain, 

 

Rxx2+Ryx2+Rzx2=0Rxy2+Ryy2+Rzy2=0Rxz2+Ryz2+Rzz2=0

 

Thus these results are the constraints of rotation matrix.