Q85. - Algebra 1

Question

Find each product.

$\left(b-7\right)\left(b+3\right)$

Step-by-Step Solution

Answer

The product of $\left(b-7\right)\left(b+3\right)$ is ${\mathit{b}}^2\mathbf{-}\mathbf{4}\mathit{b}\mathbf{-}\mathbf{21}$.

Step 1. Write distributive property.

For any numbers, $a,b$ and c, $a\left(b+c\right)=ab+ac$.

Step 2. Apply the distributive property.

Apply the distributive property to the given expression.

$b\left(b+3\right)-7\left(b+3\right)=b\cdot b+b\cdot 3-7\cdot b-7\cdot 3$

Step 3. Multiply and simplify.

Multiply terms in the above expression and simplify them further.

$b^2+3b-7b-21=b^2-4b-21$

 

Therefore, the product of $\left(b-7\right)\left(b+3\right)$ is $b^2-4b-21$.