Q.8.14

Question

A certain component is critical to the operation of an electrical system and must be replaced immediately upon failure. If the mean lifetime of this type of component is 100 hours and its standard deviation is 30 hours, how many of these components must be in stock so that the probability that the system is in continual operation for the next 2000 hours is at least .95? 

Step-by-Step Solution

Verified
Answer

 the number of components  of stocks required for given system is 

1Step 1. Given information

From the given statements of the question, we have to find out the components must be in stock so that the probability that the system is in continual operation for the next 2000 hours is at least .95.

2Step 2. finding the probability limit

Let Xi=life time of ith components given that mean lifetime μ=EXi                                                =100                     standard deviation =30 then    varience( σ2)  =302Take X=total life time of n components , so  X=i=1nXi

Based on the question lifetimes are independent random variables, so by using the properties of expectation we can write,

The random variable X with mean Ex=Ei=1nXi                                                                       =μi=1n                                                                       =                                                                     =100nVar(x)=Var(i=1nXi)=i=1nσ2                                   =2                                    =302σ2So according to the question  we have to find px>2000>0.95

3Step 3. Finding the number of components using the central limit theorem

The central limit theorem states that , states only that, for each a