Q7PE
Question
If relativistic effects are to be less than 1%, then γ must be less than 1.01. At what relative velocity is γ = 1.01?
Step-by-Step Solution
Verified Answer
The relative velocity is v = 0.140c.
1Step 1: To find the relative velocity
As we know the relativistic factor is given by
\(\gamma =\frac{1}{{\sqrt{1-{{\left({\frac{v}{c}}\right)}^2}}}}\) ... (1)
Where v is its velocity relative to an observer and c = 3.00×108 m/s is the speed of the light
Here given that the relativistic factor is
γ = 1.01
2Step 2: To solve the equation
From the equation (1 ), we get
\(\begin{aligned} v &= c\sqrt {1-{{\left( {\frac{1}{\gamma }}\right)}^2}} \\&= c\sqrt {1-{{\left( {\frac{1}{{1.01}}} \right)}^2}} \\&= 0.140c \end{aligned}\)
Hence the relative velocity is v = 0.140c.
Other exercises in this chapter
Q5PE
A neutral π-meson is a particle that can be created by accelerator beams. If one such particle lives 1.40×1048s as measured in the laborator
View solution Q6PE
A neutron lives 900 s when at rest relative to an observer. How fast is the neutron moving relative to an observer who measures its life span to be 2065s?
View solution Q8PE
If relativistic effects are to be less than 3%, then γ must be less than 1.03. At what relative velocity is γ = 1.03?
View solution Q59PE
(a) Show that \[{\left({pc}\right)^2}/{\left({m{c^2}{\rm{}}} \right)^2}{\rm{ }} = {\rm{ }}{\gamma ^2}{\rm{ }} - {\rm{ }}1\]. This means that at large veloc
View solution