Q79P - Chemistry: Molecular Nature Of Matter And Change

Question

Palladium, like its group neighbor platinum, forms four coordinate Pd(II) and six-coordinate Pd(IV) complexes. Write

modern formulas for the complexes with these compositions:

(a) PdK(NH₃)Cl₃                                                   (b) PdCl₂(NH₃)₂

(c) PdK₂Cl₆                                                         

(d) Pd(NH₃)₄Cl₄

Step-by-Step Solution

Answer

The modern formulas for the complexes are

a) $\text{K}\left[\text{Pd}\left({\text{NH}}_3\right){\text{Cl}}_3\right]$

b) $\left[\text{Pd}{\left({\text{NH}}_3\right)}_2{\text{Cl}}_2\right]$

c)${\text{K}}_2\left[{\text{PdCl}}_6\right]$

d) $\left[\text{Pd}{\left({\text{NH}}_3\right)}_4{\text{Cl}}_2\right]{\text{Cl}}_2$

Step 1: Following rules will be kept in mind before writing the formula

1. Write cation before the anion
2. charges of the cations and anions are balanced by each other
3. Write neutral ligands before anionic ligands (in alphabetical order), and the formula of the whole ion is placed in brackets
4. Write counter ions outside the brackets

Step 2: The final formulas are as follows

The modern formulas for the complexes are

a)$\text{PdK}\left({\text{NH}}_3\right){\text{Cl}}_3-\text{K}\left[\text{Pd}\left({\text{NH}}_3\right){\text{Cl}}_3\right]$

b)${\text{PdCl}}_2{\left({\text{NH}}_3\right)}_2-\left[\text{Pd}{\left({\text{NH}}_3\right)}_2{\text{Cl}}_2\right]$

c)${\text{PdK}}_2{\text{Cl}}_6-{\text{K}}_2\left[{\text{PdCl}}_6\right]$

d) $\text{Pd}{\left({\text{NH}}_3\right)}_4{\text{Cl}}_4-\left[\text{Pd}{\left({\text{NH}}_3\right)}_4{\text{Cl}}_2\right]{\text{Cl}}_2$