Q75P - Fundamentals Of Physics

Question

A certain x-ray tube operates at a current of 7.00mA and a potential difference of 80.0kV. What is its power in watts?

Step-by-Step Solution

Answer

The power of an X-ray tube is 560W.

Step 1: The given data

1. Potential difference $V=80kV or 80\times {10}^3 V$
2. Current,  $i=7mA or 7\times {10}^{-3} A$

Step 2: Understanding the concept of the power

The power of an X-ray tube can be calculated by taking the product of the current and potential difference.

 

Formula:

The equation of power that occurs due to potential difference, P = iV            (i)

Step 3: Calculation of the power

Using the given data in equation (i), we can get the power of an X-ray tube as follows:

$$\begin{gathered} P=\left(7\times {10}^{-3}\right)\times (80\times {10}^3) \\ =560W \end{gathered}$$ 

Hence, the value of the power is 560W.