Q.6.96
Question
A variable is normally distributed with a mean and a standard deviation .
a. Determine and interpret the quartiles of the variable.
b. Obtain and interpret the second decile.
c. Find the value that of all possible values of the variable exceed.
d. Find the two values that divide the area under the corresponding normal curve into a middle area of \(0.80\) and two outside areas of . Interoret vour answer.
Step-by-Step Solution
Verifieda). Quartiles: ,
,
.
b). The second decile is .
c). of observation is .
d). of all observation are between and .
Given data:
Mean .
Standard deviation .
The data is divided into four equal sections by the quartiles. The areas below the first, second, and third quartiles have proportions of , and , respectively. The scores for the proportions , and are , and , respectively, according to Table II in Appendix A.
Calculate the quartiles:
The first quartile:
The second quartile:
The third quartile:
Interpretation: of all observations are less than of all observations are less than , and of all observations are less than .
Given data:
Mean: ,
Standard deviation: .
The deciles divide the data into ten equal parts. The proportion of the area below the decile is . From Table II in the Appendix A, the - score corresponding to the proportion is .
Calculate the decile:
Interpretation:
Approximately of all observations are less than .
Given data:
Mean:
Standard deviation: .
The score corresponding to a proportion of in Table II of Appendix A is .
Calculate corresponding value:
Given data:
Mean: .
Standard deviation: .
The - scores for the proportions of regions below and , respectively, are and , according to Table II in Appendix A.
Determine corresponding values:
Interpretation:
of all observation are between and .