Q.68.

Question

Question: Cyclopropane and cyclobutane have similar strain energy despite the fact that the C-C-C bond angles of cyclopropane are much smaller than those of cyclobutane. Suggest an explanation for this observation, considering all sources of strain discussed in Chapter 4.

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Answer

Answer

The strain energies of cyclopropane and cyclobutane are similar because cyclobutane has low angle strain and high torsional strain.

 

1Step 1: Angle strain

When the angle is less than the desired angle, calculated from the hybridization of the compound, the energy of the compound rises due to increased instability. This phenomenon is called an angle strain.

For example, according to the sp3 hybridization of carbon atoms, the bond angle between the carbon and its four attached groups must be 109·50 due to tetrahedral geometry.

When an angle in any compound with sp3 carbon is smaller than 109·50 , there arises an angle strain.

2Step 2: Torsional strain

It is also called an eclipsing strain, and this strain leads to an increase in energy due to eclipsing conformation. 

3Step 3: Explanation

The interior bond angle of cyclopropane is 600 , which is too low than the desired angle, i.e., 109·50. Due to this, the energy of cyclopropane rises to a great extent.


The interior bond angle of cyclobutane is 900, which is only ~190 less than the expected angle. Hence, the angle strain of the cyclobutane ring is low.


However, cyclobutane has an eclipsing conformation due to which the energy of the molecule rises, and one of the carbon atoms from the ring puckers up. The puckered ring of cyclobutane has angles less than 900, which increases the angle strain in cyclobutane. 


Hence, the ring strain energies of cyclobutane and cyclopentane rise and attain almost similar values,that ar., 27 kcal/mol and 26 kcal/mol, respectively.

Cyclopropane ring with high angle strain


Puckered cyclobutane ring with an interior angle less than 900