Q67. - Algebra 1

Question

Evaluate each expression. (Lesson $1-2$)

$\frac{3\cdot 9^2-3^2\cdot 9}{3\cdot 9}$

Step-by-Step Solution

Answer

The value of expression is 6.

Step 1. Write the given information.

The expression given is 

$\frac{3\cdot 9^2-3^2\cdot 9}{3\cdot 9}$

Step 2. DESCRIPTION OF STEP.

To solve the given expression 

$$\begin{gathered} \frac{3\cdot 9^2-3^2\cdot 9}{3\cdot 9}=\frac{3\times \left(9\times 9\right)-\left(3\times 3\right)\times 9}{3\times 9} \\ =\frac{3\times 9\left\{9-3\right\}}{3\times 9}\left(\text{taking common terms out}\right) \\ =\left\{9-3\right\}\left(\text{cancel out the same terms in numerator and denominator}\right) \\ =6 \end{gathered}$$

Thus, $\frac{3\cdot 9^2-3^2\cdot 9}{3\cdot 9}=6$