Q66P - Chemistry: Molecular Nature Of Matter And Change

Question

Give the oxidation number of nitrogen in the following:

$$\begin{gathered} \left(a\right)\mathit{N}{\mathit{H}}_{\mathbf{2}}\mathit{O}\mathit{H} \\ \left(b\right){\mathit{N}}_{\mathbf{2}}{\mathit{F}}_{\mathbf{4}} \\ \left(c\right)\mathit{N}{\mathit{H}}_{\mathbf{4}}^{\mathbf{+}} \\ \left(d\right)\mathit{H}\mathit{N}\mathit{O} \end{gathered}$$

Step-by-Step Solution

Answer

Answer: You need to provide the oxidation no of nitrogen for the given compounds

Step 1: Oxidation state of nitrogen in NH 2 OH

Oxidation state of Hydrogen is +1.

Oxidation state of Oxygen is -2.

Let, oxidation state of nitrogen in NH₂OH is x.

No you can write,

 $$\begin{gathered} x+2\left(+1\right)+\left(-2\right)+\left(+1\right)=0 \\ x=-1 \end{gathered}$$ 

Hence, oxidation state of nitrogen in NH₂OH is -1.

 

Step 2: Oxidation state of nitrogen in N 2 F 4

Oxidation state of Flurine is -1.

Let, oxidation state of nitrogen in N₂F₄ is y.

No you can write,

  $$\begin{gathered} 2y+4\left(-1\right)=0 \\ 2y=+4 \\ y=+2 \end{gathered}$$

Hence, oxidation state of nitrogen in N₂F₄ is +2.

Step 3: Oxidation state of nitrogen in NH 3 +

Oxidation state of Hydrogen is +1.

Let, oxidation state of nitrogen in NH₃⁺ is z.

No you can write,

  $$\begin{gathered} z+4\left(+1\right)=+1 \\ z=-3 \end{gathered}$$

Hence, oxidation state of nitrogen in NH₃⁺ is -3.

Step 4: Oxidation state of nitrogen in HNO 2

Oxidation state of Hydrogen is +1.

Oxidation state of Oxygen is -2.

Let, oxidation state of nitrogen in HNO₂ is k.

No you can write,

  $$\begin{gathered} \left(+1\right)+k+2\left(-2\right)=0 \\ k=+3 \end{gathered}$$

Hence, oxidation state of nitrogen in HNO₂ is +3.