Q66. - Algebra 2

Question

A school conference room can seat a maximum of 83 people. The principal and two counselors need to meet with the school’s student athletes to discuss eligibility requirements. If each student must bring a parent with them, what is the maximum number of students that can attend each meeting?

Step-by-Step Solution

Answer

The required answer is 40.

Step 1- Define the required variable

Consider x be the count of students. 

Step 2 – Form the equation

Take the variable and form the equation by using that the two times of count of students plus the count of other three members is equal to the limit of the seats.

$2x+3=83$

Step 3- Solve the equation for x

Perform subtraction of 3 from both sides of the equation.

$\begin{array}{c}2x+3-3=83-3\\ 2x=80\end{array}$

Perform division of 2 on both sides of the equation. 

$\begin{array}{c}\frac{2x}{2}=\frac{80}{2}\\ x=40\end{array}$

Step 4- Perform the checking

Perform the addition between the count of students, parents and other three members.

$40+40+3=83$

This results in the provided limit of seats which means that the obtained answer is correct.