Q.65 - Intermediate Algebra

Question

For the function $g\left(x\right) = 4 - 36x$, find:

$ⓐ g\left(3\right) ⓑ g\left(0\right) ⓒ g(-1)$

Step-by-Step Solution

Answer

The value of $g\left(3\right)$ for the given function is $-104$.

The value of $g\left(0\right)$ for the given function is $4$.

The value of $g(-1)$ for the given function is $40$.

Step 1. Given Information

The given polynomial function is $g\left(x\right)=4-36x$

The given value function is $g\left(3\right), g\left(0\right), g(-1)$

Part (a) Step 1. The given function is g ( x ) = 4 - 36 x The given value function is g ( 3 ) . Putting the x = 3 in the given function.

The given function is $g\left(x\right) = 4 - 36x$

putting $x=3$

$$\begin{gathered} g\left(3\right)=4-36\times 3 \\ g\left(3\right)=4-108 \\ g\left(3\right)=-104 \end{gathered}$$

Part (b) Step 1. The given polynomial function is   g ( x )   =   4   −   36 x .

The given value function is $g\left(0\right)$

Part (b) Step 2. Putting the x = 0 in the given function.

The given function is $g\left(x\right) = 4 - 36x$

putting $x=0$

$$\begin{gathered} g\left(0\right)=4-36\times 0 \\ g\left(0\right)=4-0 \\ g\left(0\right)=4 \end{gathered}$$

Part (c) Step 1. The given polynomial function is   g ( x )   =   4   −   36 x .

The given value function is $g(-1)$

Part (c) Step 2. Putting the x = - 1 in the given function.

The given function is $g\left(x\right) = 4 - 36x$

putting $x=-1$

$$\begin{gathered} g(-1)=4-36\times (-1) \\ g(-1)=4+36 \\ g(-1)=40 \end{gathered}$$