A patient with a dislocated shoulder is put into a traction apparatus as shown in Fig. P1.63.The pulls A→and B→ have equal magnitudes and must combine to produce an outward traction force of 12.8 N on the patient’s arm.How large should these pulls be?

Q63 P - University Physics with Modern Physics

Q63 P

Question

A patient with a dislocated shoulder is put into a traction apparatus as shown in Fig. P1.63.The pulls $\vec{A}$ and $\vec{B}$ have equal magnitudes and must combine to produce an outward traction force of 12.8 N on the patient’s arm.

How large should these pulls be?

Step-by-Step Solution

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Answer

The patient’s arm should be pulled is, $A = B = 7.55 N$

1Identification of given data

The outward traction force is, $R_{x} = A_{x} + B_{x} = 12.8 N$ .
The displacement vector of arm is, $A_{x} + B_{x}$ .

2Concept of Traction force

Tactile force, or traction, is the force utilized to induce motion between an object and a tangential surface.

Wet friction is the most typical method of generating motion between two bodies, however shear force applied to the tangential surface may also be utilized.

3Determine magnitude of pull

The resultant force can be evaluated as,

$R_{x} = A_{x} + B_{x}$

$R_{x} = A \cos 32 ° + B \cos 32 °$

Since, $A = B$ .

So,

$2 A \cos 32 ° = R_{x}$

$A = \frac{R_{x}}{2 (\cos 32 °)}$

$A = \frac{12.8 N}{2 \cos 32 °}$

$A = 7.55 N$

The magnitude of force in $A_{x}$ ,

$A_{x} = A \cos 32 °$