Q62E

Question

Identify any carbon atoms that change hybridization and the change in hybridization during the reactions in Exercise 20.39.

Step-by-Step Solution

Verified
Answer

a) From \(s{p^2}\) to \(s{p^3}.\)

b) From \(s{p^3}\) to \(s{p^2}.\)

1Step 1:The reaction of 2-butene with water in dilute acid

a) 2-butene is an alkene that has 4 carbon atoms in a straight chain while a double bond exists between carbon atoms 2 and \(3.\)

Since there is a double bond and water molecule, we can assume that water will be added to the double bond.

This reaction follows Markovnikov's rule, which says that the H atom is added to the less substituted carbon atom.

Acid serves as a catalyst in this reaction.

Then, the OH group is added to a more substituted carbon atom - in this case, it's either one because alkene is symmetrical and equally substituted.

The reactions with Lewis structures and condensed molecular formulas



                                             Reaction (a)

2Step 2: The hybridization change

The two carbon atoms in the middle that share a double bond are \(s{p^2}\)hybridized because of the planar arrangement that the double bond causes.

On the other hand, as they react, they tend to have 4 single bonds around them, like the other two carbon atoms.

The tetrahedral arrangement means \(s{p^3}\)hybridization after the reaction.

3Step 3: The dehydration reaction of ethanol

b) Let's observe the dehydration reaction of ethanol

Ethanol consists of 2 carbon atoms and one OH group.

Dehydration is a process where water is removed from a molecule.

Here the \(OH\)group will be removed along with the \(H\)atom or carbon atom adjacent to the \(C\)atom that has attached to the \(OH\)group.

Electrons from the C-H bond will be used to form a new \(\pi \)bond and make a double bond between two carbon atoms.



                                                         Reaction (b)

4Step 4: The tetrahedral arrangement

In benzene, there is a tetrahedral arrangement which means that \(s{p^3}\)hybridization is present.

By dehydrating ethanol, ethene is made as a product

Ethene has a double bond between its 2 carbon atoms.

This type of structure can only take a planar configuration, which means hybridization is \(s{p^2}.\)