Q.62 - Algebra 2

Question

$\frac{10y-2}{3}+3=\frac{10y+1}{9}$

Step-by-Step Solution

Answer

The value of $y=-1$

Step 1 - The given information

$\frac{10y-2}{3}+3=\frac{10y+1}{9}$

Step 2

$$\begin{gathered} \frac{10y-2}{3}+3=\frac{10y+1}{9} \\ \Rightarrow \frac{10y-2}{3}-\frac{10y+1}{9}=-3 \\ \Rightarrow \frac{3(10y-2)-(10y+1)}{9}=-3 \\ \Rightarrow \frac{30y-6-10y-1}{9}=-3 \\ \Rightarrow 20y-7=-27 \\ \Rightarrow 20y=-20 \\ \Rightarrow y=-1 \end{gathered}$$