Q60. - Algebra 1

Question

CONSTEUCTIPH A new gym is being built at Greenfield Middle School. The length of the gym as shown on the builder's blueprints is $12\text{ inches}$. Find the actual length of the new gym.

Step-by-Step Solution

Answer

The actual length of the gym is $80\text{ft}$.

Step 1. Given information.

The length of the gym as shown on the builder's blueprints is $12\text{ inches}$.

The scale is $=\frac{3}{5}\text{ inches}=5\text{ feet}$.

Step 2. To find the length of the new gym.

The length of the gym on the blueprints is $12\text{ inches}$.

As the given scale,

$\begin{array}{l}\frac{3}{4}\text{in}=5\text{ft}\\ \Rightarrow \text{1 in}=5\times \frac{4}{3}\text{ft}\\ \Rightarrow \text{1 in}=\frac{20}{3}\text{ft}\\ \Rightarrow \text{12 in}=\frac{20}{3}\times \text{12ft}\\ \Rightarrow \text{12 in}=20\times 4\text{ft}\\ \Rightarrow \text{12 in}=80\text{ft}\end{array}$

Step 3. Conclusion.

Hence, the actual length of the gym is $80\text{ft}$. $12$