Q6 E
Question
How many \({\rm{\sigma }}\)and \({\rm{\pi }}\)bonds are present in the molecule HCN?
Step-by-Step Solution
Verified Answer
Two \({\rm{\sigma }}\) bonds and two \({\rm{\pi }}\) bonds make up HCN.
1Step 1: Definition of Concept
The sigma bond is formed when two half-filled atomic orbitals involved in the formation of a molecular orbital overlap along the internuclear axis.
The bond formed is known as a pi-bond when half-filled p-orbitals involved in bond formation overlap sideways.
2Step 2: How many bonds are present in the molecule HCN
The bonds are below:
\(H - C \equiv N\)
Therefore, the two \({\rm{\sigma }}\) bonds and two \({\rm{\pi }}\) bonds make up HCN.
Other exercises in this chapter
Q4E
Use valence bond theory to explain the bonding in\({{\rm{F}}_2},{\rm{HF}}\), and\({\rm{ClBr}}\). Sketch the overlap of the atomic orbitals involved in the bonds
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Use valence bond theory to explain the bonding in\({{\rm{O}}_{\rm{2}}}\). Sketch the overlap of the atomic orbitals involved in the bonds in \({{\rm{O}}_{\rm{2}
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A friend tells you \({{\rm{N}}_{\rm{2}}}\)has three \({\rm{\pi }}\)bonds due to overlap of the three p-orbitals on each N atom. Do you agree?
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Draw the Lewis structures for \({\rm{C}}{{\rm{O}}_{\rm{2}}}\)and\({\rm{CO}}\), and predict the number of \({\rm{\sigma }}\) and \({\rm{\pi }}\) bonds for each m
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