Q5PE - College Physics (Urone)

Question

Soccer fields vary in size. A large soccer field is 115 m  long and 85 m  wide. What are its dimensions in feet and inches? (Assume that  1 meter  equals  3.281 feets).

Step-by-Step Solution

Answer

The dimension for length in feet is  377.2 ft  and  278.8 ft  respectively. 

The dimension for width in inches is  4527.55  and  3346.45 inch  -respectively. 

The length of a figure, which is its longest dimension, indicates how long an item or figure is. Linear units  such as meters, centimeters, inches and other measurements are used to convey it. 

The shorter distance of an item or a figure is its width, which indicates how wide or broad the provided figure is.

Step 1: Given data

Consider the given data as below.

Length of the soccer field, I = 115 m

Width of the soccer field, w = 85 m

Step 2: Conversion of units

$$\begin{gathered} 1 \mathrm{meter}= 3.28 \mathrm{foot} \\ 1 \mathrm{meter}= 39.37 \mathrm{inch} \end{gathered}$$

Step 3: Calculation of dimensions in feet

The length of the soccer field,-

$$\begin{gathered} \mathrm{I}=115 \mathrm{m}\times \frac{3.28 \mathrm{ft}}{1 \mathrm{m}} \\ =377.2 \mathrm{ft} \end{gathered}$$

The width of the soccer field,-

$$\begin{gathered} \mathrm{w}=85 \mathrm{m}\times \frac{3.28 \mathrm{ft}}{1 \mathrm{m}} \\ =278.8 \mathrm{ft} \end{gathered}$$

Hence, the dimension for length in feet is  377.2 ft  and  278.8 ft respectively. 

Step 4: Calculation of dimensions in inches

The length of the soccer field,-

$$\begin{gathered} \mathrm{I}=115 \mathrm{m}\times \frac{39.37 \mathrm{inch}}{1 \mathrm{m}} \\ =4527.55 \mathrm{inch} \end{gathered}$$

The width of the soccer field

$$\begin{gathered} \mathrm{w}=85 \mathrm{m}\times \frac{39.37 \mathrm{inch}}{1 \mathrm{m}} \\ =3346.45 \mathrm{inch} \end{gathered}$$

Hence, the dimension for width in inches is  $4527.55 \mathrm{inch}$ and $3346.45 \mathrm{inch}$  respectively.