Q59. - Algebra 2

Question

Find the slope of the line that passes through each pair of points.

$\left(-\mathbf{5},\mathbf{0}\right)$, $\left(\mathbf{4},\mathbf{0}\right)$

Step-by-Step Solution

Answer

The slope of the required straight line is 0.

Step 1 – State the concept

The slope of a straight-line passing through the points $\left(h,k\right)$ and $\left(a,b\right)$ is given as $m=\frac{b-k}{a-h}$.

Step 2 – List the given data

It is given that the line passes through $\left(-5,0\right)$ and $\left(4,0\right)$.

Then, $\left(h,k\right)=\left(-5,0\right)$ and $\left(a,b\right)=\left(4,0\right)$.

Step 3 – Find the slope

Put $\left(h,k\right)=\left(-5,0\right)$ and $\left(a,b\right)=\left(4,0\right)$ in $m=\frac{b-k}{a-h}$ to get,

$\begin{array}{l}m=\frac{0-0}{4-\left(-5\right)}\\ =\frac{0}{4+5}\\ =\frac{0}{9}\\ =0\end{array}$

So, $m=0$ 

So, the slope of the required straight line is 0.