Q58P

Question

Two ropes in a vertical plane exert equal-magnitude forces on a hanging weight but pull with an angle of 72.0° between them. What pull does each rope exert if their resultant pull is 372 N directly upward?

Step-by-Step Solution

Verified
Answer

The pull exerted by each rope is 230 N.

1Identification of given data

The given data can be listed below,

  • The angle at which ropes are pulled is, θ=72°.
  • The resultant pull exerted is, F=372 N.
2Significance of the force

Force is equal to the rate of momentum change with respect to time in any given situation, which facilitates the acceleration of an object

3Determination of pull exerted by the ropes

The magnitude of resultant of the components of two vectors in the y-direction is given by,

Cy=Ay+By

Here,  Ay is the magnitude of y-component of force A, By is the magnitude of y-component of force B
and Cy is the magnitude of resultant of forces,A and B.

Assuming y-axis lies along the north, the three vectors, their magnitudes and their direction are shown in the diagram given below,

                             

                                   


The magnitude of the two vectors is equal. and they make equal angle θ with the y-axis.

Therefore,

Ay=By    =Acosθ    =Acos 36°

Substitute values in the equation of resultant force, the value of A is given by,

 A cosθ+B cosθ=CyA cos 36°+A cos 36°=372                    2A cos 36°=372                                     A=230 N

Thus, the pull exerted by each rope is 230 N.