Q5.8P - Chemistry: Molecular Nature Of Matter And Change

Question

Convert the following:

(a) 0.745 atm to mmHg                  (b) 992 torr to bar

(c) 365 kPa to atm                           (d) 804 mmHg to kPa

Step-by-Step Solution

Answer

1. The pressure of 0.745 atmis 566.2 mmHg.
2. The pressure of 992 torrsin bar unit is 1.32 bar.
3. The pressure of 365 kPa in atm unit is 3.60 atm.
4. The pressure of 804 mmHg in kPa unit is 106.9 kPa.

Step 1: Conversion for (a)

1 atm = 760 mmHg

The conversion of 0.745 atm to mmHg is,

 $0.745 atm \times \frac{760 mmHg}{1 atm} = 566.2 mmHg$

Thus, the pressure in the mmHg unit is 566.2 mmHg.

Step 2: Conversion for (b)

Torr and bar are related as follows:

1 torr = 0.00133 bar

The conversion of 992 torr to bar is,

 $992 torr \times \frac{0.00133 bar}{1 torr} = 1.32 bar$

Thus, the pressure in the bar unit is 1.32 bar.

Step 3: Conversion for (c)

kPa and atm are related as,

1 kPa = 0.00987 atm

The conversion of 365 kPa to atm is,

 $365 kPa \times \frac{0.00987 atm}{1 kPa} = 3.60 atm$

Thus, the pressure in the atm unit is 3.60 atm.

Step 4: Conversion for (d)

MmHg and kPa are related as,

 1 mmHg = 0.133 kPa

The conversion of 804 mmHg to kPa is,

 $804 mmHg \times \frac{0.133 kPa}{1 mmHg} = 106.9 kPa$

Thus, the pressure in the kPa unit is 106.9 kPa.